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JJ为202t,求助思路

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匿名  发表于 1970-1-1 08:00:00
地板
发表于 2003-7-24 21:36:00 | 只看该作者
以下是引用bettyofarim在2003-7-24 15:59:00的发言:
12) s is a product of two integers from 100 to 200 inclusive, t is a product of two integers from 100 to 201 inclusive, what is the value of (1/s)+(1/t)?


JJ为202t,求助思路 ,怎么确定S 和T中的那2个数那?


I think there is some problem in this question... it is different from the question I read in one JJ, though similar...the problem is we can't get two specific numbers, how can we dicide the value of s and t?
wondering....
板凳
发表于 2003-7-24 17:03:00 | 只看该作者
pls explain in detail.
沙发
发表于 2003-7-24 16:18:00 | 只看该作者
1/s=1/(100*----200); 1/t=1/(100*-----201)  通分相加后即可.这是五月的JJ.应该很容易的.你的问题"怎么确定S 和T中的那2个数那?"是什么意思,那两个数是什么数呀?
楼主
发表于 2003-7-24 15:59:00 | 只看该作者

JJ为202t,求助思路

12) s is a product of two integers from 100 to 200 inclusive, t is a product of two integers from 100 to 201 inclusive, what is the value of (1/s)+(1/t)?


JJ为202t,求助思路 ,怎么确定S 和T中的那2个数那?
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