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You need to try all operations +, – , and x so try all operator for: k.1 is not equal to 1.k for some numbers k. (-) k-1 is not equal to 1-k , RIGHT , SOME NUMBERS ARE YES (+) k+1 is not equal to 1+k , WRONG , ALL NUMBERS ARE EQUAL (x) kx1 is not equal to 1xk , WRONG , ALL NUMBERS ARE EQUAL so you can get the rigth operator = substraction.
so try the substraction – first: k. (l+m)=(k.l) + (k.m) => k- (l+m)=(k-l) + (k-m) => k-l-m = k-l+k-m (move l & m on the left side into the right side) => k=k-l+k-m+l+m => k=0 so you can get k=0 with substraction.
so the answer is D. EACH statement ALONE is sufficient. |
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