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问一道纠结的数学题 prep上的

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楼主
发表于 2011-5-4 11:53:31 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
1.the  rate of  a certain chemical reaction is directly proportional to the square of the concentration of chemical Apresent and inversely proportional to the concertration of chemicalB present. If the concentration of chemical B is increased by 100 percent, which of the following is closet to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
40%increase? 50%increase?

2.what could be correct order? 1/x,2x,x*2
1)x*2<2x<1/x  2)x*2<1/x<2x 3) 2x<x*2<1/x
答案是1和2,不知道第二个是怎么解出来的

3. when a certain tree was first planted, it was 4feet tall, and the height of the tree increased by a constant amount each year for the next 6years, At the end of the 6th year,  the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
3/10  
2/5
1/2
2/3
6/5
这题我怎么算都是1/10,
请教各路牛人帮帮忙啦~十分感谢
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沙发
发表于 2011-5-4 12:16:02 | 只看该作者
1 is a chemistry question.

rate = n*[A]^2/[B]  If [B] becomes 2[B], then [A] has to become 1.41[A] to compensate that increase in B.

2.what could be correct order? 1/x,2x,x*2
1)x*2<2x<1/x  2)x*2<1/x<2x 3) 2x<x*2<1/x
答案是1和2,不知道第二个是怎么解出来的

Try x = 5/7
板凳
发表于 2011-5-4 12:19:39 | 只看该作者
3. when a certain tree was first planted, it was 4feet tall, and the height of the tree increased by a constant amount each year for the next 6years, At the end of the 6th year,  the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
3/10  
2/5
1/2
2/3
6/5

h(n) = 4 + a*n
h(6) = 4 + 6a
h(4) = 4 + 4a
h(6)-h(4) = (1/5)*h(4)
2a = (1/5)*(4 + 4a)
6a =4
a = 2/3
地板
 楼主| 发表于 2011-5-4 23:40:22 | 只看该作者
[quote]
1 is a chemistry question.

rate = n*[A]^2/  If becomes 2, then [A] has to become 1.41[A] to compensate that increase in B.

问一下哈 这1.41是不是指的是根2啊?

还有"1/5taller than" 我怎么觉得是比第四年多1/5的意思啊 求教求教~~

5#
 楼主| 发表于 2011-5-4 23:54:11 | 只看该作者
牛人啊!
我一般做这题的时候狂带数~不如你这方法严谨!
谢啦哈!
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