上飞机之前放狗新+阅读 而是期号

ghyj123

输血：1.140个东西，m个人分，m大于等于2，每人至少分一个，问有多少种分法？
2.DS：一种定义1,2,3,4,5,6.。。。。。  1,2,3,4,5可以看成1,23,45，so N等于1+23+45=68.反正就是中间必须有两个是连起来的，问N是偶数？
1  12连起来 2  N是个三位数
3.a=2de8次方  b=2的a次方    求a的b次方是多少
上飞机了。。。回去再想！！！
阅读：讲恐龙的，好像是说在北美好像是发现一个恐龙骨头，说他们的腿部骨骼连接处没有连接好，但是牙齿磨得很好，说明它们的妈妈照顾的它们很好。第二段说不对，有一个人也发现一个骨头化石证明这个不对，举个别的动物例子说明，因此类推的话第一段的观点是不对的。

windychen0089

I think this math question is the same as the one I solved on another thread:

今天考试碰到一道诡异输血让人很惊奇。现在有1 2 3 4 5 五个数，随意组合成三个相加，得出的数x能有1 2 3 4 5 表示。
比如：  12+34 +5=51
DS题， 下面什么情况下能保证所加之和x为偶数。
（1）X是3位数
(2)有一个 加号在1 2中间， 如 31+42。。。

For this question, it is important to realize that the one's digit of the three numbers has to be chosen from two setups of (2, 4, 5) and (3, 4, 5) because the one's digit of x has to be chosen from 1-5, more like only 1 or 2. Any if only one setup works under the condition, that condition is sufficient.

1) insufficient. 123 +4 +5=132,  132 +4 +5= 141
2) inufficient. 32 +14 + 5 = 51, 23 + 14 + 5 = 42

1) and 2) together: Since 1 and 2 has to be separated and X is a 3-digit number, then we have to go with the (2,4,5) setup.  The reason is that for the (3, 4, 5) setup, 1 and 2 have to be together in order to have x greater than 100. But this is not alowed in condition (2).  So we have to go with (2, 4, 5).

One possible example is 2 + 314 + 5 = 321

So 1) and 2) together will give an odd number.

Choose E since none conditions can give you an EVEN number, although 1) and 2) can give you an even number.

-- by 会员 sdcar2010 (2010/12/29 3:30:08)

I think this math question is the same as the one I solved on another thread:

今天考试碰到一道诡异输血让人很惊奇。现在有1 2 3 4 5 五个数，随意组合成三个相加，得出的数x能有1 2 3 4 5 表示。
比如：  12+34 +5=51
DS题， 下面什么情况下能保证所加之和x为偶数。
（1）X是3位数
(2)有一个 加号在1 2中间， 如 31+42。。。

For this question, it is important to realize that the one's digit of the three numbers has to be chosen from two setups of (2, 4, 5) and (3, 4, 5) because the one's digit of x has to be chosen from 1-5, more like only 1 or 2. Any if only one setup works under the condition, that condition is sufficient.

1) insufficient. 123 +4 +5=132,  132 +4 +5= 141
2) inufficient. 32 +14 + 5 = 51, 23 + 14 + 5 = 42

1) and 2) together: Since 1 and 2 has to be separated and X is a 3-digit number, then we have to go with the (2,4,5) setup.  The reason is that for the (3, 4, 5) setup, 1 and 2 have to be together in order to have x greater than 100. But this is not alowed in condition (2).  So we have to go with (2, 4, 5).

One possible example is 2 + 314 + 5 = 321

So 1) and 2) together will give an odd number.

Choose E since none conditions can give you an EVEN number, although 1) and 2) can give you an even number.

-- by 会员 sdcar2010 (2010/12/29 3:30:08)

If it is like what you said " So 1) and 2) together will give an odd number" , then you need to choose the answer C instead of  E,  because you know the answer is "NO".

For me, choosing E is because when, for example, 1+2+534=537 it is a odd number and when, for another example, 1+345+2=348, but it's an even number. The two samples above both meet the criterias:（1）X是3位数
(2)有一个 加号在1 2中间， 。。。so we cannot answer the quesiton if N is an even number or a odd number, choose answer E. I don't know if my reasoning is right!

AlohaDJ

OH...You have given the solution to the above question!

sdcar2010

I think this math question is the same as the one I solved on another thread:

今天考试碰到一道诡异输血让人很惊奇。现在有1 2 3 4 5 五个数，随意组合成三个相加，得出的数x能有1 2 3 4 5 表示。
比如：  12+34 +5=51
DS题， 下面什么情况下能保证所加之和x为偶数。
（1）X是3位数
(2)有一个 加号在1 2中间， 如 31+42。。。

For this question, it is important to realize that the one's digit of the three numbers has to be chosen from two setups of (2, 4, 5) and (3, 4, 5) because the one's digit of x has to be chosen from 1-5, more like only 1 or 2. Any if only one setup works under the condition, that condition is sufficient.

1) insufficient. 123 +4 +5=132,  132 +4 +5= 141
2) inufficient. 32 +14 + 5 = 51, 23 + 14 + 5 = 42

1) and 2) together: Since 1 and 2 has to be separated and X is a 3-digit number, then we have to go with the (2,4,5) setup.  The reason is that for the (3, 4, 5) setup, 1 and 2 have to be together in order to have x greater than 100. But this is not alowed in condition (2).  So we have to go with (2, 4, 5).

One possible example is 2 + 314 + 5 = 321

So 1) and 2) together will give an odd number.

Choose E since none conditions can give you an EVEN number, although 1) and 2) can give you an even number.

sdcar2010

LS NN，为什么不考虑数字3。。？？

-- by 会员 AlohaDJ (2010/12/29 2:03:38)

Oops!

ghyj123

只能两个数字相连  可以往后+数字的  需要的话可以1,2,3,4,5,6,7,8     所以可以1+2+3+45+6+78

AlohaDJ

LS NN，为什么不考虑数字3。。？？

sdcar2010

2.DS：一种定义1,2,3,4,5,6.。。。。。  1,2,3,4,5可以看成1,23,45，so N等于1+23+45=68.反正就是中间必须有两个是连起来的，问N是偶数？
1  12连起来 2  N是个三位数

1) 12+4+5+6 = odd, 12+456 = even.  Insufficient
2) N is a 3-digit number. 123 + 4 + 56 = even.  123 +45 +6 = odd.  Insufficient

1) and 2) 12 + 345 = odd. 12 + 354 = even  Insufficient.

scauhyl

marked~~~lz h rp

ghyj123

不是  答案貌似是2的18次方   我题干的数字可能不对