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求助一道PREP题···完全不知道他在讲什么哇··

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楼主
发表于 2010-10-7 23:29:35 | 只看该作者 回帖奖励 |正序浏览 |阅读模式
If 500 is the multiple of 100 that is closest to x and 400 is the multiple of 100 that is closest to y. Which multiple of 100 is closest to x+y?
(1). x<500
(2). y<400

啥意思啊?求牛牛指教···
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7#
 楼主| 发表于 2010-10-8 09:06:54 | 只看该作者
谢谢楼上···大牛一生平安···
6#
发表于 2010-10-8 00:33:54 | 只看该作者
题目的意思是500是和x相差最小的整百数
即450<x<550
400是与y相差最小的整百数
350<y<450
那么x+y的话就是 800<x+y<1000
(1)when x<500, then 450<x<500, 800<x+y<950
   与x+y相差最小的整百数可以是800 也可以是900 ---not sufficient
   (也可举反例证明 当x=460, y=360时,x+y=820, 答案是800;
   当x=490, y=440时, x+y=930, 答案是900)
剩下的用同样的思路
5#
发表于 2010-10-8 00:28:56 | 只看该作者
If 500 is the multiple of 100 that is closest to x and 400 is the multiple of 100 that is closest to y. Which multiple of 100 is closest to x+y?
(1). x<500
(2). y<400

SOLUTION.
From the first part of the sentence, get 450<x<550 and from the second part, 350<y<450.
(1) If x<500, then 450<x<500, i.e. 800<x+y<950, the mutiple of 100 that is closeset to x+y will be 800 or 900.
(2) If y<400, then 350<y<400, i.e. 800<x+y<950, the mutiple of 100 that is closeset to x+y will be 800 or 900 as well.
When (1) and (2) are both held,
then 450<x<500 and 350<y<400, i.e. 800<x+y<900, the mutiple of 100 that is closeset to x+y will be 800 or 900 as well.

So, (1) combined with (2) is not sufficient.

The key is E. Is it right?
地板
发表于 2010-10-8 00:26:36 | 只看该作者
答案是E吗?
Both together are not sufficient
板凳
 楼主| 发表于 2010-10-7 23:58:45 | 只看该作者
顶啊···求指教啊···
沙发
发表于 2010-10-7 23:42:02 | 只看该作者
同问~这道题我也做错了,实在是不明白在说什么==
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