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小弟不才....多题询问

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匿名  发表于 1970-1-1 08:00:00
沙发
发表于 2008-6-13 19:59:00 | 只看该作者

答案,不对请更正:

     7E: h(100) + 1=2^50(50!)+1,次数被50以下的任何数除都余1,其最小公约数必定大于50,

         也就大于40,所以E

      27D:<73 且 >69

      39E:26字母的可以重复使用的排列,26+26^2+26^3

      41C:做法同上题

      48D:就一个DISTRICT小,设最小为X,其他10个都是他的1.1倍,有10(1.1X),合起来X+10(1.1X)=132000,所以X=11000

楼主
发表于 2008-6-13 19:35:00 | 只看该作者

小弟不才....多题询问

7.     905-!-item-!-187;#058&000575

For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive.  If p is the smallest prime factor of h(100) + 1, then p is

 

(A) between 2 and 10

(B) between 10 and 20

(C) between 20 and 30

(D) between 30 and 40

(E) greater than 40

27.    3330-!-item-!-187;#058&003295

38, 69, 22, 73, 31, 47, 13, 82

Which of the following numbers is greater than three-fourths of the numbers but less than one-fourth of the numbers in the list above?

 

(A) 56

(B) 68

(C) 69

(D) 71

(E) 73

39.    5583-!-item-!-187;#058&004668

A certain stock exchange designates each stock with a one-, two-, or three-letter code, where each letter is selected from the

26 letters of the alphabet.  If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?

 

(A)  2,951

(B)  8,125

(C)  15,600

(D)  16,302

(E)  18,278

41.    5676-!-item-!-187;#058&004686

All of the stocks on the over-the-counter market are designated by either a 4-letter or a 5-letter code that is created by using the 26 letters of the alphabet.  Which of the following gives the maximum number of different stocks that can be designated with these codes?

 

(A) 2(26^5)

(B) 26(26^4)

(C) 27(26^4)

(D) 26(26^5)

(E) 27(26^5)

48.    6225-!-item-!-187;#058&004914

A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district.  What is the minimum possible population that the least populated district could have?

 

(A) 10,700

(B) 10,800

(C) 10,900

(D) 11,000

(E) 11,100

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