陈向东一道数学题 求助各位大神

mnmicy

     Cars X and Y were traveling together on a straight road at a constant speed of 55 miles per hour when car X stopped for 5 minutes. If car Y continued to travel at 55 miles per hour, how many minutes from the time that car X resumed traveling did it take car X traveling at 60 miles per hour to catch up with car Y ？ (Assume that the time for car X to slow down and speed up was negligible.)

                        A．5
        B．30
        C．45
        D．55（对）
        E．60


各位大神  能否帮忙给解答一下。万分感谢！！！



  

mnmicy

Teriyaki83 发表于 2020-10-8 22:38
在X停的五分钟里 Y走了55/12 miles 后面X和Y的速度差距是5miles/h 也就是说1小时里X比Y多走5miles 所以需要 ...

感谢 感谢

Teriyaki83

在X停的五分钟里 Y走了55/12 miles 后面X和Y的速度差距是5miles/h 也就是说1小时里X比Y多走5miles 所以需要的时间是路程除以速度 也就是（55/12）/5=11/12h 也就是55分钟