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郁闷,第一次做数学,错了很多

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楼主
发表于 2014-2-9 12:03:41 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
OG  13开始的评估部分,数学两个部分各自都只对了11题
我怎么也是正儿八经的双学位,工程本科和计算机本科
太差了



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沙发
发表于 2014-2-9 12:38:28 来自手机 | 只看该作者
才第一次,不急,慢慢来
板凳
发表于 2014-2-9 20:39:28 | 只看该作者
郁闷无用,关键是不浪费时间,想想尼克胡哲
地板
发表于 2014-2-9 22:23:43 | 只看该作者

In a certain board game, a stack of 48 cards, 8 of which represent shares of stock, are shuffled and then placed face down.  If the first 2 cards selected do not represent shares of stock, what is the probability that the third card selected will represent a share of stock?

(A)  1/8 (B)  1/6 (C)  1/5 (D)  3/23 (E)  4/23



19. 2463-!-item-!-187;#058&002761  For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative.  What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

  (A) One (B) Two (C) Three (D) Four (E) Five

刚才解答了这个帖子,楼主可以看下G数学的难点主要在读题,G数学不难,不过不能轻视,主要是读懂题目,
顺便再粘贴下我的解答,希望对楼主有帮助
第一题,难点是:, 8 of which represent shares of stock,  因为是“非重要语句”,所以被两个都好分开了,读的时候先跳过,即: a stack of 48 cards, are shuffled and then placed face down(然后再补充进来),即,被拿走两个,还剩46个,问拿到那八个的概率  选E
第二题,难点是:the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative   这个一个定义句,读懂才能做,SC典型分析句,即:
(the number of variations in sign) (is defined as )(the number of pairs )(of consecutive terms of the sequence)( for which the product of the two consecutive terms is negative)  中文对应翻译为:(个数。。。。)(被定义为)(一对数的个数)(什么样的一对数呢:连续的序列,即连续的数)(什么样的乘机呢: 即连续两个数的乘机为负数)(的定义)
选C

祝楼主杀G顺利
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