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Problem:
Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 10 inches on a side and costs $10, and a large pizza that measures 15 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?
My thoughts:
Step 1 --
$30:
$10x3=$30 _ 10*2 x 3=300 square inches
$10+$20=$30 _ 10*2 + 15*2=325 square inches
so put them together, options are: 1) 300+300=600 2) 300+325=625 3) 325+325=650
Step 2 --
$60:
$10 x 6=$60 _ 10*2 x 6=600
$40+$20=$60 _ 10*2 x4+15*2=625
$20+$40=$60 _ 10*2 x2+15*2 x2=625
$20 x 3=$60 _ 15*2 x3=675
Step 3 --
675-600=75
or 675-625=50
or 675-650=25
However! The answer is:
[size=11.000000pt] 25 [size=11.000000pt]square inches: [size=11.000000pt]First, figure the area of each pizza: the small is 100 square inches, and the largeis 225 square inches. If the two friends pool their money, they can buy three large pizzas, which have atotal area of 675 square inches. If they buy individually, though, then each friend will have to buy onelarge pizza and one small pizza, so they will only have a total of 2(100 + 225) = 650 square inches ofpizza.
Why is my thinking against the Manhattan answer??
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发表于 2015-5-12 22:06:44
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