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弱问Prep DS1 41

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发表于 2010-6-20 04:24:46 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
41.3690-!-item-!-187;#058&003497

Machines X and Y work at their respective constant rates.How many more hours does it take machine Y, working alone, to fill a production order of a certain size than it takes machine X, working alone?



(1) Machines X and Y, working together, fill a production order of this size in two-thirds the time that machine X, working alone, does.



(2) Machine Y, working alone, fills a production order of this size in twice the time that machine X, working alone, does.

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答案】E

work=1, machineX=Xhour, machineY=Yhour, y-x=?


我的理解是从(2) 来看,Y比X没效率, 同是完成1项任务,Y的耗时是X的2倍 ,也就是y =2x  ,  或者 用速度来表示就是 2/y = 1/x

这个刚好和详解版的列式相反。

请NN讲解我的理解哪里错了?
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沙发
发表于 2010-6-20 05:21:34 | 只看该作者
通过条件2 就如你说的 很快可得出x,y的速度比是 2:1
通过条件1 其实也可以算出 x和y的 速度比 为2比1

但是这两个条件里算出来的都只是比值 完全没有涉及具体的 hours.

所以E
板凳
发表于 2011-4-28 09:33:31 | 只看该作者
我觉得要是设X的时间为x hour,Y的时间为y hour的话··
应该是1)    2/3(1/x+y/1)=1/x
          2)    y=2x
地板
发表于 2013-8-16 06:51:53 | 只看该作者
以下摘录自曼哈顿论坛, 原帖请看 http://www.manhattangmat.com/forums/machine-x-and-y-work-at-their-respective-constant-rates-ds-t4339.html

Let x and y represent the respective rates of X and Y.
We must know the values of both x and y to know “how many more hours”. In other words, y = 2x does not tell us how many more hours the job takes Y than X, only that Y takes twice as long. If x = 2, y = 4 and the difference is 2. However, if x = 3, y = 6, and it now takes 3 hours longer.

1) 1/x + 1/y = 1/T
So, T (total time) = xy / (x+y)
Statement 1 tells us that the total time or combined = 2/3 x
So, xy / (x+y) = 2/3 x
Solve and you get y = 2x
INSUFFICIENT – again, it only gives us a relationship

2) translated gives y = 2x

Statements 1 and 2 provide the same information, so either D or E
Since we cannot combine 2 similar equations to solve for 2 variables, the answer is E
5#
发表于 2014-3-15 17:36:05 | 只看该作者
appletree1987 发表于 2013-8-16 06:51
以下摘录自曼哈顿论坛, 原帖请看 http://www.manhattangmat.com/forums/machine-x-and-y-work-at-their-res ...

D谢!!
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