上几道PREP，求解求解~~@~！！~！！

你说过等我 · 发表于 2011-8-7 10:27:57

1. for a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1,3,2,5, -4,-6? A 1 B 2 C 3 D 4 E5 (题目就没看懂，求解释。。求做法)

2. 整数X能被6整除吗？
（1）X+3能被3除
（2）X+3是奇数
选C，可是条件（2）是怎么用的呢？？

3.Each person attending a party was charged the same asmission fee, how many people attended the party.
(1) if fee had been $0.75 less and 100 more people had attended, the party would have received the same amount in fee.
(2)if fee had been $1.5 more and 100 fewer people had attended, the party would have received the same amount in fee.

选C ，咋做的？？

谢谢大家~！~！~！

schlaf · 发表于 2011-8-7 10:43:46

第一题是说在一个确定的序列中，number variations定义为序列中连续一对树，这两个数的乘机为负数，问有几个number variations，是不是一对啊

第二题，x+3=3k，x=3（k-1），除非k-1是2的倍数，所以条件一不能确定。条件二x+3为奇数，那么x为偶数，x=2，4,6，不确定
两个条件一起，x为偶数，那么k-1为2的倍数，可以确定x被6整除

schlaf · 发表于 2011-8-7 10:58:03

第三题，收入为f*n，第一个条件说，（f-0.75）*（n+100）
第二个条件（f+1.5）*（n-100）
上面两个式子都等f*n，根据两个条件可以求出n

你说过等我 · 发表于 2011-8-7 11:43:21

第三题：if fee had been $0.75 less and 100 more people had attended,这句话怎么翻译的啊？本人还很菜鸟，拜托帮我翻下谢啦！1

第一题答案是3 个。。。很纠结啊。。

jeffxu · 发表于 2011-8-7 11:50:34

schlaf的解答是对的，第一题答案应该是1。
第三题，虚拟语气，如果没人费用比原来少0.75，同时人数多100的话...

jeffxu · 发表于 2011-8-7 11:52:04

确认了一下，我的prep原题，数字为1, -3, 2, 5, -4, -6，这样答案就是3了。

你说过等我 · 发表于 2011-8-7 11:58:44

谢谢~~~谢谢~~··`~~~原来是我抄错了。。。。

上几道PREP，求解求解~~@~！！~！！

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