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[原创]GWD13-8

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楼主
发表于 2005-11-14 10:54:00 | 只看该作者

[原创]GWD13-8

Q8:


At a certain food stand, the price of each apple is ¢ 40 and the price of each orange is ¢ 60.  Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is ¢ 56.  How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is ¢ 52?



A. 1


B. 2


C. 3


D. 4


E. 5



When the average (arithmetic mean) price of the 10 pieces of fruit is ¢ 56


apple =2, orange=8   



(0.4*2+0.6*8)/10=0.56



when the average price of the pieces of fruit that she keeps is ¢ 52


apple =4, orang=6



(0.4*4+0.6*6)/10=0.52



the key should be B (8-6=2), Why the answer gives E?

沙发
发表于 2005-11-14 11:32:00 | 只看该作者

题目意思是说减少orange的数量使得平均价格降低,并不是说总数不变.

板凳
发表于 2010-10-4 13:05:21 | 只看该作者
照楼上所说,那这道题该怎么算啊?
地板
发表于 2010-10-4 13:16:32 | 只看该作者
2苹果 8橘子
再拿走橘子的话就是总数=10-X了
所以 40*2+60(8-X)=52(10-X)
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