Q8:
At a certain food stand, the price of each apple is ¢ 40 and the price of each orange is ¢ 60. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is ¢ 56. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is ¢ 52?
A. 1
B. 2
C. 3
D. 4
E. 5
When the average (arithmetic mean) price of the 10 pieces of fruit is ¢ 56
apple =2, orange=8
(0.4*2+0.6*8)/10=0.56
when the average price of the pieces of fruit that she keeps is ¢ 52
apple =4, orang=6
(0.4*4+0.6*6)/10=0.52
the key should be B (8-6=2), Why the answer gives E?  |