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GWD25 23 米有问过的

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楼主
发表于 2010-8-6 09:47:47 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
?Q23.
At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?

(1) The number of oranges sold at the fruit stand
  yesterday was 5 more than the number of
  apples.

(2) The total revenue from the sale of apples
  at the fruit stand yesterday was $15.00
答案是C,但是我觉得两个条件加起来都推不出来啊,有米有谁能讲讲怎么算的?谢谢
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沙发
发表于 2010-8-6 09:55:41 | 只看该作者
我觉得答案有问题吧。。。应该是C吧。。。
板凳
发表于 2010-8-6 09:56:46 | 只看该作者
Number of apples = N
Number of oranges = N + 5
Price of each orange = x
Price of each apple = x + 0.1

N(x+0.1) = 15
显然解不出来啊。。。。。我也疑惑。。。
地板
发表于 2010-8-6 10:05:56 | 只看该作者
在别的网上找到证明C是错的

As the number of apples is 5 more than the no of oranges, so the minimum no of apples is 6.
假设苹果卖掉6个or8个
Revenue from the sale of apples = 15=6*2.5 ---1 or
                                                     8*1.875-----2


For case 1, revenues for oranges would be 1*2.4 =2.4
Total 2.4+15 = 17.4

Case 2

3*(1.875-.1) = 5.325

Total revenues = 5.325+15 = 20.325


两种答案不一样

所以不可能选C
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