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prep的一道题

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楼主
发表于 2010-2-6 00:59:59 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
Of the 75 houses in a certain community, 48 have a patio.  How many of the houses in the community have a swimming pool?



(1) 38 of the houses in the community have a patio but do not have a swimming pool.



(2) The number of houses in the community that have a patio and a swimming pool is equal to the number of houses in the community that have neither a swimming pool nor a patio.

此题我怎么都想不通为什么只用第二个条件就可以算出答案

                                      patio   no-patio

                       pool           a            b

                     no-pool        c            a  

                                      48           27(75-48)

以上就是单靠第二个条件所能得出的信息,how could it get the answer directly...???

   
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沙发
发表于 2010-2-6 01:08:40 | 只看该作者
LZ画个图吧,就是那种两个圈圈相交的图...
然后你就会惊讶地发现,只有游泳池而没有露台的人数,加上两个都有的人数,就等于拥有游泳池的人数,,,而两个都有的,等于两个都没有的...而两个都没有的加上只有游泳池的,就是75-48...
板凳
 楼主| 发表于 2010-2-6 01:13:13 | 只看该作者
感谢LS!顺便想问一下为什么我那种方法算不出结果呢?我一直以为那种方法万能的...

thx again
地板
发表于 2010-2-6 01:26:00 | 只看该作者
Of the 75 houses in a certain community, 48 have a patio.  How many of the houses in the community have a swimming pool?



(1) 38 of the houses in the community have a patio but do not have a swimming pool.



(2) The number of houses in the community that have a patio and a swimming pool is equal to the number of houses in the community that have neither a swimming pool nor a patio.

此题我怎么都想不通为什么只用第二个条件就可以算出答案

                                      patio   no-patio

                       pool           a            b

                     no-pool        c            a  

                                      48           27(75-48)

以上就是单靠第二个条件所能得出的信息,how could it get the answer directly...???

   
-- by 会员 dontwannalose (2010/2/6 0:59:59)



just use your information:


a + b + a + c = 75 (total house)
a + c = 48 (house with patio)
question: a + b = ? (house with pool)


hehe, do you see the answer now?
5#
 楼主| 发表于 2010-2-6 01:30:59 | 只看该作者
right...got u...thx u, both of u, so much indeed
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