prep两道数学题~~不解啊。。。求助

dolorez · 发表于 2009-12-6 22:38:30

1. In the fraction x/y, where x and y are positive integers, what is the value of y?

The least common denominator of x/y and 1/3 is 6.

X=1.

2. For manufacturer M, the cost of producing X units of its product per month is given by c=kx+t, where c is in dollars and k and t are constants. Last month if manufacturer M produced 1000 units of its product and sold all the units for k+60 dollars each, what was manufacturer M’s gross profit on the 1000 units?

Last month, Manufacturer M’s revenue from the sale of the 1000 units was 150,000

Manufacturer M’s cost of producing 500 units in a month is 45,000 less than its cost of producing 1000 units in a month.

dolorez · 发表于 2009-12-8 21:54:42

help help~~~

celineyo · 发表于 2009-12-8 21:58:12

正确答案是什么呀？

dolorez · 发表于 2009-12-8 22:24:45

两个答案都是E

sprtng · 发表于 2009-12-8 22:33:57

1. 是E么，如果x是1，那y可能是2 或者 6...
2. 应该也是E吧，只能求出K是90来， c跟t都是未知。。。

dolorez · 发表于 2009-12-8 22:43:58

第二题1的条件可以算出k,然后2的条件代入C方程不也可以求出那两个定量么

dolorez · 发表于 2009-12-8 22:50:29

就是K=90，然后2的条件代入式45000=90乘以500+t，不就可以算出T吗

sprtng · 发表于 2009-12-9 00:56:48

2. For manufacturer M, the cost of producing X units of its product per month is given by c=kx+t, where c is in dollars and k and t are constants. Last month if manufacturer M produced 1000 units of its product and sold all the units for k+60 dollars each, what was manufacturer M’s gross profit on the 1000 units?

Last month, Manufacturer M’s revenue from the sale of the 1000 units was 150,000

Manufacturer M’s cost of producing 500 units in a month is 45,000 less than its cost of producing 1000 units in a month.

第二题我列出来的式子是:
1. 1000(k+60) = 150000
2. 500*k - t +45000 = 1000k - t

t被cancel掉啦。。。还是求不出t到底是多少来，所以总的cost还是未知

eric603 · 发表于 2009-12-9 05:50:44

一楼正解两个都是e

1) Y=2 OR Y=6 => E

2) 条件1，2 其实都只能单独求出k=90, t未知，＝》E

prep两道数学题~~不解啊。。。求助

帮帮忙啊，谢谢！！

答案是e

我

我的解法

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