If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?D
your second attempt; 2^5(your choices) * C5,3(couples); you included the choices from two couples you did not pick, those two couples you did not pick each has 2 choices which would compute to 2^2, thats your extra factor