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prep两题

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楼主
发表于 2006-12-6 21:31:00 | 只看该作者

prep两题

Each employee on a certain task force is either a manager or a director.What percentage of the employee on the task force are directors?
(1)The average salary of the managers on the task force is $5,000 less than the average salary of all employee on the task force.
(2)The average salary of the directors on the task force is $15,000 greater than the average salary of all employee on the task force.

答案是C,不明白..我觉得算不出来啊

On a certain sight-seeing tour,the ratio of the number of women to the number of children was 5 to 2.What was the number of men on the sight-seeing tour?
(1)On the sight-seeing tour,the ratio of the number of children to the number of men was 5 to 11.
(2)The number of women on the sight-seeing tour was less than 30.

答案C,(2)并没有给出WOMEN数啊..怎么得出MEN数的?

沙发
发表于 2006-12-6 22:43:00 | 只看该作者

1,设M,D分别有x,y人,求X/Y,设平均A

A-5000x+A+15000y=A(x+y) à15000y=5000x

W : C=5:2

1) CM=511

2W 少于30,为5倍数

      设为25C10M22 一组

              设为20C8M88/5

              设为15C6M66/5

              设为10C4M44/5

              设为5C2M11/10

如此只有第一组满足。

板凳
发表于 2006-12-7 11:24:00 | 只看该作者
第2题,综合两个条件得:

    

W:C=5:2; C:M=5:11;

W:C:M=5:222/5) 所以W=5k, C=2k, M=(22/5),所以k5的倍数,

k<6 所以k=5,所以M=22


    
地板
发表于 2006-12-7 11:25:00 | 只看该作者
漏写了一个k, 应该是:

第2题,综合两个条件得:

    

W:C=5:2; C:M=5:11;

W:C:M=5:222/5) 所以W=5k, C=2k, M=(22/5)k, 所以k5的倍数,

k<6 所以k=5,所以M=22


    
5#
 楼主| 发表于 2006-12-7 13:58:00 | 只看该作者

恩..懂啦

谢谢大家

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