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Gmat prep Maths-谢谢

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楼主
发表于 2006-10-13 10:11:00 | 只看该作者

Gmat prep Maths-谢谢

On his way to work, Leo listens to one of three radio stations, A, B, or C. He first turns to A, if A is playing a song he likes, he listens to it; if not, he turns to B. If B is playing a song he likes, he listens to it, if not he turns to C. If C is playing a song he likes, he listens to it, if not, he turns off the radio. For each station the probability is 0.3 that at any given moment the station is playing a song he likes. On his way to work, what's the probability that Leo will hear a song he likes. ( answer: 0.657)

此题无思路,请各位帮助

沙发
发表于 2006-10-13 10:17:00 | 只看该作者

看错题了,嘿嘿

最先听a频道,遇到喜欢的歌的可能性是0.3

如果a 频道的不喜欢,听b频道,可能性为0.7*0.3,因为a频道的不好听

类似听c频道是0.7*0.7*0.3

加起来就是答案了


[此贴子已经被作者于2006-10-13 10:21:29编辑过]
板凳
发表于 2006-10-13 12:31:00 | 只看该作者
更簡單的方法:
1-關機的機率=碰到好聽歌曲的機率
1-(3/10)^3 = 1 - 343/1000 = 0.657
地板
 楼主| 发表于 2006-10-13 21:08:00 | 只看该作者
thank you!
5#
发表于 2006-10-13 22:03:00 | 只看该作者
以下是引用Shadowx在2006-10-13 12:31:00的发言:
更簡單的方法:
1-關機的機率=碰到好聽歌曲的機率
1-(3/10)^3 = 1 - 343/1000 = 0.657

应该是1-(7/10)^3
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