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GWD9 3道数学难题求助

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楼主
发表于 2006-8-30 16:43:00 | 只看该作者

GWD9 3道数学难题求助

Q20:

 

 

Favorable

Unfavorable

Not Sure

Candidate M

40

20

40

Candidate N

30

35

35

 

The table above shows the results of a survey of 100 voters each responded “favorable” or “unfavorable” or “not sure” when asked about their impressions of candidate M and of candidate N.  What was the number of voters who responded “favorable” for both candidates?

(1)    The number of voters who did not respond “favorable” for either candidate was 40.

(2)    The number of voters who responded “unfavorable” for both candidates was 10.

                         

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

Q13:

If the sequence x1, x2, x3, …, xn, … is such that x1  = 3 and xn+1
                
= 2xn – 1 for n ≥ 1, then x20 x19 =

 

A.       219

B.       220

C.      221

D.      220 - 1

E.       221 - 1

Answer:

Q8:

The points R, T, and U lie on a circle that has radius 4.  If the length of arc RTU is , what is the length of line segment RU?

 

A.  3/4    

B.  8/3    

C.      3

D.      4

E.       6

Answer:
                

沙发
发表于 2006-8-30 18:03:00 | 只看该作者

第二道

答案A:可先求出 x2=5 

             又根据已知可得x20 x19= 2x19
                            
x18

              同理                   x19 x18=
                                        
21x18
                                            
x17

              所以                   x20 x19 =22x18
                                                    
x17

              。。。。           x20 x19 =218x2
                                                                
x1=  219

板凳
 楼主| 发表于 2006-8-30 19:54:00 | 只看该作者

这样啊,谢谢!

地板
发表于 2006-8-30 20:51:00 | 只看该作者

第三道

答案:D   已知弧长求弦长解法:先求弦或弧对应的圆心角:360*弧长/圆周长

          本题为360*4/3/8=60因此
                
 RUO是个等边三角形

5#
发表于 2006-8-30 21:05:00 | 只看该作者

第一道:

答案是:A        由1条件可知欢迎两个候选人的人集合是60人 ,是由分别欢迎两人的40和30人

                 的集合的并集,因此可得出都欢迎VOTERS是10人

                 由2则无法推出来

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