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Try (x+y
If (x+y)^2 and (x-y)^2 are the powers of 2,then the value of the equation is 2^4xy, thus the result is 16.
谢谢 i know。 lianxyz 考试 成功
xy=1
2^(x+y)^2/2^(x-y)^2=2^(x+y)^2-(x-y)^2
=2^4xy
= 2^4
=16
Hope it will be helpful.
谢谢啦
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