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gwd-5-3

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楼主
发表于 2006-7-12 11:06:00 | 只看该作者

gwd-5-3

Q3:

If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible? C15C14C16

A.     20

B.     40

C.     50

D.     80

E.      120

the answer is D,mine is E

沙发
发表于 2006-7-12 11:15:00 | 只看该作者
C(5,3)C(2,1)C(2,1)C(2,1)=80
板凳
 楼主| 发表于 2006-7-12 12:51:00 | 只看该作者
谢谢指正!
地板
发表于 2006-7-24 12:28:00 | 只看该作者

sorry,i still don't really understand this question..

is it means that if 5 married couples actually are 10 people.

it would be very kind if anybody could give us a better and comprehensive explanation...

thank u..

5#
发表于 2006-7-24 12:41:00 | 只看该作者

C(10,1)*C(8,1)*C(6,1)/P(3,3)

 

6#
发表于 2006-7-24 12:52:00 | 只看该作者

c(10 3)-5c(8 1)

7#
发表于 2006-7-24 13:49:00 | 只看该作者

thank you all......

lovetiky,it's very clear why C(10,1)C(8,1)C(6,1)comes out,however,why this product need to be divised by P(3,3).

8#
发表于 2006-7-24 14:19:00 | 只看该作者
以下是引用citicsbond在2006-7-24 13:49:00的发言:

thank you all......

lovetiky,it's very clear why C(10,1)C(8,1)C(6,1)comes out,however,why this product need to be divised by P(3,3).

the product of Combination contains the order, but there is no order in the committee.
[此贴子已经被作者于2006-7-24 14:33:00编辑过]
9#
发表于 2006-7-24 14:27:00 | 只看该作者

没有顺序就要除吗?对不起,我知道接下来让你解释,肯定bother u.但是,还是不理解。

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