ChaseDream
搜索
返回列表 发新帖
查看: 1889|回复: 4
打印 上一主题 下一主题

[求助]GWD-20-3/20-5/20-11/20-36/20-37

[复制链接]
楼主
发表于 2006-6-8 02:02:00 | 只看该作者

[求助]GWD-20-3/20-5/20-11/20-36/20-37

Q3:

For all positive integers m and v, the expression m Θ v represents the remainder when m is divided by v.  What is the value of  ?

 

 

A.     -10

B.     -2

C.     8

D.     13 answer

E.      17

看不懂題目,請幫忙.

Q11:

If 36x = 8,100, what is the value of (3x – 1)3 ?

 

 

A.     90

B.     30

C.     10

D.     10/3 answer

E. 10/9

解到8100=3^4x100便不行了

Q5: DS

If k, m, and t are positive integers and k/6+m/4=t/12, do t and 12 have a common factor greater than 1 ?

(1)     k is a multiple of 3.

(2)     m is a multiple of 3.

answer=a

Q36:

If a and b are positive integers such that ab and a/b are both even integers, which of the following must be an odd integer?

 

 

A.     a/2

B.     b/2

C.     (a+b)/2

D.     (a+2)/2

E.      (b+2)/2

我覺得如d是odd,那a也應是odd,為什麼answer是d?

Q37:

During a trip, Francine traveled x percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 60 miles per hour.  In terms of x, what was Francine’s average speed for the entire trip?

 

 

A.      (180-X)/2

B.      (X+60)/4

C.      (300-X)/5

D.     600/(115-X)

E.      12000/(X+200) answer

請問怎樣得e?


沙发
发表于 2006-6-8 04:18:00 | 只看该作者
Please post the questions separately next time.

3. m Θ v = x where x + n*v = m (n is a positive integer)

5. k/6 + m/4 = t/12 => k/3 + m/2 = t/6 => 2k + 3m = t
condition 1: let k = 3x => 6k + 3m = t => 3(2k + m) = t => t is a multiple of 3
condition 2: let m = 3y => 2k + 9m = t (inconclusive)

11. (3x – 1)3 = 3 ^ (3x - 3) = 3^3x / 3^3 = 3^(6x * 0.5) / 27 = (3^6x)^0.5 / 27 = 8100^0.5 / 27 = 90/27 = 10/3

36.
a-b = even => a and b are either both even or both odd
a/b = even => a and b are both even and a is a multiple of 4 (4x / 2y = 2x/y)

let a = 4x (x is an integer)
=> a/2 = 2x (still even)
=> (a+2)/2 = (4x + 2)/2 = 2x+1 (odd)

37. let total distance = y and z = x/100 (percentage)
total time = (y*z)/ 40 + (y*(1-z))/60 = (3zy + 2y - 2zy) / 120 = (zy + 2y) / 120
average speed = total distance / total time = y / [(zy + 2y) / 120]
= 120 / (z + 2) = 12000 / (x + 200)
板凳
发表于 2006-6-8 08:47:00 | 只看该作者

对,题目要分开写出题号,以便后人查找。

标题我已改,类似这样GWD-20-3/20-5/20-11/20-36/20-37就可以了。

或者下次可按单题发贴。

地板
 楼主| 发表于 2006-6-8 13:20:00 | 只看该作者
Thanks a lot, and next time I will post the question one by one.
5#
发表于 2010-8-14 20:27:23 | 只看该作者
按一个爪印
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2025-6-14 01:40
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2025 ChaseDream.com. All Rights Reserved.

返回顶部