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[考古] 关于余数的问题

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楼主
发表于 2019-11-6 21:49:35 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
关于一个余数的题有点疑问,大家一起探讨一下,谢谢
原题在这,是yu2x总结的余数专题,感谢她:https://forum.chasedream.com/for ... 7&extra=&highlight=余数&page=1
另外关于余数的总结还有:https://forum.chasedream.com/thread-437516-1-1.html

Practice: If x is an integer, is x between 27 and 54?
(1) The remainder when x is divided by 7 is 2.
(2) The remainder when x is divided by 3 is 2.

Sol:
STAT1: The remainder when x is divided by 7 is 2.
x = 7k + 2
Possible values of x are 2,9,16,...,51,...
we cannot say anything about the values of x
so, INSUFFICIENT
STAT2: The remainder when x is divided by 3 is 2.
x = 3s + 2
Possible values of x are 2,5,8,11,...,53,...
we cannot say anything about the values of x
so, INSUFFICIENT
STAT1+STAT2
:now there are two approaches

1. write the values of t from stat1 and then from stat2 and then take the common values
from STAT1 x = 2,9,16,23,30,37,44,51,58,...,65,...
from STAT2 x = 2,5,8,...,23,...,44,...,59,65,...
common values are x = 2,23,44,65,...
2. equate x = 7k+2 to x=3s+2
we have 7k + 2 = 3s+2
k = 3s/7
since, k is an integer so only those values of s which are multiple of 7 will satisfy both STAT1 and STAT2
so, common values are given by x = 3s + 2 where s is multiple of 7
so x = 2,23,44,65 (for s=0,7,14,21 respectively)
Clearly there are values of x which are between 27 and 54 (i.e. 44) and those which are not (2,23,65)
So, both together also INSUFFICIENT

So, answer will be E



我的疑问是划线部分:当STAT1+STAT2时,因为x在27~54之间,所以不是只有唯一解为44吗,为什么不是选d??




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沙发
发表于 2019-11-6 21:56:23 | 只看该作者
23啊,23除7余2  ,23除3也余2.
板凳
 楼主| 发表于 2019-11-6 22:00:27 | 只看该作者
月球的人 发表于 2019-11-6 21:56
23啊,23除7余2  ,23除3也余2.

x在27~54之间...
地板
发表于 2019-11-6 22:01:38 发自 iPhone | 只看该作者
700wansui 发表于 1分钟前
x在27~54之间...

题目问你x是不是在这之间,那23就不在这之间,44在这之间,所以就不能确定是不是x一定在这之间。
5#
发表于 2019-11-6 22:02:41 发自 iPhone | 只看该作者
700wansui 发表于 2分钟前
x在27~54之间...

DS题目,是要确定的,如果算出来有两个不一样的结果就不能算是充分。
6#
 楼主| 发表于 2019-11-6 22:03:44 | 只看该作者
月球的人 发表于 2019-11-6 22:01
题目问你x是不是在这之间,那23就不在这之间,44在这之间,所以就不能确定是不是x一定在这之间。 ...

同意!               
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