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[求助]gwd-28-30

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楼主
发表于 2006-6-18 12:55:00 | 只看该作者

[求助]gwd-28-30

Q30:

A rectangular photograph is surrounded by a border that is 1 inch wide on each side.  The total area of the photograph and the border is M square inches.  If the border had been 2 inches wide on each side, the total area would have been (M + 52) square inches.  What is the perimeter of the photograph, in inches?

 

A.      34

B.      36

C.      38

D.     40

E.      42

I can only until

xy=M

(x+1)(y+1)=M+52

(x+1)(y+1)-xy=52

(x+2)y-xy=52

and solve x=25, y=26.

But can't find the perimeter=40, which is D.

Can anyone please help?

Thank you very much.

沙发
 楼主| 发表于 2006-6-18 16:04:00 | 只看该作者

But according to , x=25, y=26, the answer is 2(25+26)=82

how come?


[此贴子已经被作者于2006-6-19 11:51:53编辑过]
板凳
发表于 2006-6-19 09:16:00 | 只看该作者
 (x+1)*(y+1) = M; (x+2)*(y+2) = M + 52
地板
发表于 2007-8-29 18:07:00 | 只看该作者
以下是引用hitlzc在2006-6-19 9:16:00的发言:
 (x+1)*(y+1) = M; (x+2)*(y+2) = M + 52

这样算下来, x+y=49, 所以photograph的周长是98, 那位xdjm给验算一下。感谢!!


[此贴子已经被作者于2007-8-29 18:11:27编辑过]
5#
发表于 2008-7-26 03:38:00 | 只看该作者
x+y=20
6#
发表于 2018-1-14 10:18:15 | 只看该作者
(x+2)*(y+2) = M;  (x+4)*(y+4) = M + 52
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