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跪求数学大神帮忙 。好运送你

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楼主
发表于 2017-10-29 22:01:32 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

Tanya prepared 4 different letters to be sent to 4 different addresses.  For each letter, she prepared an envelope with its correct address.  If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?
(A)1/24
(B) 1/8
(C) 1/4
(D) 1/3
(E)3/8  

选D 求过程


One kilogram of a certain coffee blend consists of x kilogram of type I coffee and y kilogram of type II coffee.  The cost of the blend is C dollars per kilogram, where C = 6.5x + 8.5y.  Is x < 0.8 ?
(1) y > 0.15

(2) C 大于等于7.3

这题选B。。。。怎么感觉答案是错的。。。

For any positive integer n, the length of n is defined as the number of prime factors whose product is n.  For example, the length of 75 is 3, since 75 = 3*5*5.  How many two-digit positive integers have length 6?
(A) None
(B) One
(C) Two
(D) Three

(E) Four

这题选C。。 一直都是记答案,却不知道算的过程

Is the integer n odd?
(1) n is divisible by 3.

(2) 2n is divisible by twice as many positive integers as n.

这题选B 条件2 怎么理解呢? 谢谢




The figure shown represents a board with four rows of pegs, and at the bottom of the board are four cells numbered 1 to 4.  Whenever the ball shown passes through the opening between two adjacent pegs in the same row, it will hit the peg directly beneath the opening.  The ball then has probability   of passing through the opening immediately to the left of that peg and probability   of passing through the opening immediately to the right.  What is the probability that when the ball passes through the first two pegs at the top it will end up in cell 2?
(A) 1/16
(B) 1/8
(C) 1/4
(D) 3/8

(E) 1/2

这题选D




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沙发
 楼主| 发表于 2017-10-30 10:32:04 | 只看该作者
板凳
发表于 2017-10-30 13:22:14 | 只看该作者
第一题,给信和信封编号abcd和ABCD,总共有A44=24种对应方式。题目说只有一组是对应的,假设只有A和a是对的,那其它组都不对应情况只有两种BCD对应cdb or dbc。所以总共对应的情况有2*4种。概率就是8/24=1/3。
第二题,由题目可以知道Y=X-1。然后(1)X<0.85 不能知道
(2)将Y=X-1带入算就知道啦
第三题 范围是10—99 lag length 要6的话 先考虑最小的素数2作为因子的情况,2的6次=64,然后往上加大,2的5次*3=96,再大就不可能了,所以就只有两个
第四题 如果N是奇数的话,那2N的因子个数是N的两倍,因为直接在原来N因子的基础上乘以2的数全部都是2N的因子
地板
发表于 2017-10-30 13:29:06 | 只看该作者
打错了。。。第二题Y=1-X
5#
 楼主| 发表于 2017-10-30 14:30:58 | 只看该作者
Gracece 发表于 2017-10-30 13:22
第一题,给信和信封编号abcd和ABCD,总共有A44=24种对应方式。题目说只有一组是对应的,假设只有A和a是对的 ...

非常感谢你。祝你好运连连。
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