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一道好题,值得讨论

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楼主
发表于 2005-7-1 06:58:00 | 只看该作者

一道好题,值得讨论

24. A certain airport security scanner designed to detect explosives in luggage will alert the scanner’s operator whenever the piece of luggage passing under the scanner contains an explosive. The scanner will erroneously alert the operator for only one percent of the pieces of luggage that contain no explosives. Thus in ninety-nine out of a hundred alerts explosives will actually be present.

The reasoning in the argument is flawed because the argument

(A) ignores the possibility of the scanner’s failing to signal an alert when the luggage does contain an explosive
(B) draws a general conclusion about reliability on the basis of a sample that is likely to be biased
(C) ignores the possibility of human error on the part of the scanner’s operator once the scanner has alerted him or her
(D) fails to acknowledge the possibility that the scanner will not be equally sensitive to all kinds of explosives
(E) substitutes one group for a different group in the statement of a percentagey
沙发
发表于 2005-7-1 07:18:00 | 只看该作者
what is the ansewr? I would like to choice E

板凳
发表于 2005-7-1 11:21:00 | 只看该作者

A

地板
发表于 2005-7-1 14:47:00 | 只看该作者
C  
5#
发表于 2005-7-1 17:14:00 | 只看该作者
i choose A
6#
发表于 2005-7-1 19:18:00 | 只看该作者

俺选E。


关键是对最后一句话的理解。

7#
发表于 2005-7-1 19:51:00 | 只看该作者

选A。原文推理过程是:


前提:100次的alert中只有一次错误,其余都对(都有explosives)。


结论:无论什么时候都可以detect!第一句:A certain airport security scanner designed to detect explosives in luggage will alert the scanner’s operator whenever the piece of luggage passing under the scanner contains an explosive.


flaw:前提说的是detect到的情况,但还有scanner没有detect到的情况。没有说scanner会detect所有含explosive的luggage。A正好是。

8#
发表于 2005-7-1 23:00:00 | 只看该作者
E
9#
 楼主| 发表于 2005-7-2 00:20:00 | 只看该作者

应该是E


cause : The scanner will erroneously alert the operator for only one percent of the pieces of luggage that contain no explosives.  (scanner 有1%的错误率:会将没有炸药的认为有)


conclusion: in ninety-nine out of a hundred alerts explosives will actually be present. (100次警示中99中会有炸药)


但是,1%的概率并不表示是刚好100件里有一件,可能1000件里有10件,而这10件可能一起出现在前100件中,这样不就在100件中有10件误警. E 选项说明了这个问题,所以对


E ) substitutes one group for a different group in the statement of a percentagey

10#
发表于 2005-7-2 14:57:00 | 只看该作者

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