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马上考试~求助一道prep数学题 settled

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楼主
发表于 2012-8-8 20:44:24 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
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沙发
发表于 2012-8-8 21:10:06 | 只看该作者
Suppose the number of manager is 1, and the number of director is n, if we can caculate n, surely we can find the percentage of directors
for (1): S(m) + n* S(d) = (S(m) + 5000)*(1+n);
for (2): S(m) + n * S(d) = (S(d)  - 15000) *(1+n);

==> S(d) - S(m) = 20000;  and S(m) + n*S(d) = S(m) + nS(m) + 5000 + 5000n
==> n(S(d)-S(m)) = 5000 + 5000n ==> 20000n = 5000 + 5000n ==> n = 1/3

So the percent of Directors is n/1+n , (1)+(2) is sufficient.
板凳
发表于 2012-8-8 21:22:19 | 只看该作者
我这道题当时的时候也不会
地板
 楼主| 发表于 2012-8-8 21:23:41 | 只看该作者
Suppose the number of manager is 1, and the number of director is n, if we can caculate n, surely we can find the percentage of directors
for (1): S(m) + n* S(d) = (S(m) + 5000)*(1+n);
for (2): S(m) + n * S(d) = (S(d)  - 15000) *(1+n);

==> S(d) - S(m) = 20000;  and S(m) + n*S(d) = S(m) + nS(m) + 5000 + 5000n
==> n(S(d)-S(m)) = 5000 + 5000n ==> 20000n = 5000 + 5000n ==> n = 1/3

So the percent of Directors is n/1+n , (1)+(2) is sufficient.
-- by 会员 greengreed (2012/8/8 21:10:06)



超清晰~~太感谢了~~
5#
 楼主| 发表于 2012-8-8 21:24:31 | 只看该作者
我这道题当时的时候也不会
-- by 会员 ATWer (2012/8/8 21:22:19)



我觉得特复杂~~
6#
发表于 2012-8-8 21:34:37 | 只看该作者
现在想想明白了,列一个等式(a-5000)x+(a+15000)y=(x+y)a。展开以后能得出x:y,就可以了,所以选C
7#
 楼主| 发表于 2012-8-8 21:39:51 | 只看该作者
Suppose the number of manager is 1, and the number of director is n, if we can caculate n, surely we can find the percentage of directors
for (1): S(m) + n* S(d) = (S(m) + 5000)*(1+n);
for (2): S(m) + n * S(d) = (S(d)  - 15000) *(1+n);

==> S(d) - S(m) = 20000;  and S(m) + n*S(d) = S(m) + nS(m) + 5000 + 5000n
==> n(S(d)-S(m)) = 5000 + 5000n ==> 20000n = 5000 + 5000n ==> n = 1/3

So the percent of Directors is n/1+n , (1)+(2) is sufficient.
-- by 会员 greengreed (2012/8/8 21:10:06)



nn能不能再帮我看一道题啊~
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8#
发表于 2012-8-8 22:07:58 | 只看该作者
for (1), replace x ==> 12u = 8y + 12 ==> 3*4*u = 4*2*y+ 3*4, we can only sure 3 is a factor is y but can't sure 2 or 2*2 is also a factor of y. LCD not sure.
for (2), replace y ==> x = 8*3*4*z + 3*4= (3*4)(8z+1), as x must be divided by 3*4, we can sure know the LCD is 3*4. because y already includes 3*4 as a factor.
9#
发表于 2012-8-8 22:09:17 | 只看该作者
1. x=12u,12u=8y+12, 化简得y=3(u-1)/2,u等于3和5的时候最大公约数是3和6,不一样,所以无法得出
2. y=12z,   x=8*12z+12, 化简得x=12(8z+1),又因为y=12z,8z+1和z不能再约,8z+1/z=8+1/z,除非z为1,但是z为1时最大公约数还是12,所以就能确定了

所以选B
10#
 楼主| 发表于 2012-8-8 22:29:18 | 只看该作者
for (1), replace x ==> 12u = 8y + 12 ==> 3*4*u = 4*2*y+ 3*4, we can only sure 3 is a factor is y but can't sure 2 or 2*2 is also a factor of y. LCD not sure.
for (2), replace y ==> x = 8*3*4*z + 3*4= (3*4)(8z+1), as x must be divided by 3*4, we can sure know the LCD is 3*4. because y already includes 3*4 as a factor.
-- by 会员 greengreed (2012/8/8 22:07:58)



恩~明白了~~感谢~~
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