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一道PP里的题, 求解

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楼主
发表于 2011-4-9 10:27:26 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
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沙发
发表于 2011-4-9 10:53:43 | 只看该作者
Basically,
1) These consecutive natural numbers h(100) and [h(100) + 1]  are co-prime, meaning that they do not share any prime numbers as their cofactors.  
2) h(100) contains all the prime numbers between 2 (from 2) and 47 (from 94).
3) Then prime numbers among factors of [h(100) + 1] would not include any prime numbers between 2 and 47.
4) Then the smallest prime facotr of [h(100) + 1] is bigger than 47.
板凳
 楼主| 发表于 2011-4-9 10:55:03 | 只看该作者
非常有帮助, 多谢大大
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