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书学讨论:狗87 V2

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楼主
发表于 2011-1-11 11:35:53 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
<v2> 11DS已知一个群体200人中有人选A课,有人选B课。(还是说两种语言神马的忘了……),问选A课而不选B课的有多少人
1)两种课都选的人和两种课都不选的人一样多
2)选A课不选B课的人是选B课不选A课的人的两倍


V2 总人数=A+B-两种都参加+均不参加

条件1这两个人数一样无法计算条件2 设两种都参加的是x 计算式A-X=2(B-X) 可计算出,选B

我感觉应该选E,请大虾指教
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沙发
发表于 2011-1-11 12:58:52 | 只看该作者
200 people.  X only choose A. Y only choose B. Z choose both A and B.  N choose neither.

200 = X + Y + Z + N.
A = X + Z (A is a known number)
B = Y + Z (B is a known number)

The stimulus asks for X

1) Z = N.  Then
200 = X + Y + 2Z.  
A = X + Z (A is a known number)
B = Y + Z (B is a known number)

But this won't help us since if you add the 2nd and 3rd equation, you would get the same equation (A +B has to equal 200, though).  Insufficient.

2) X = 2Y.  Then
200 = 2Y + Y + Z + N = 3Y + Z + N
A = 2Y + Z (A is a known number)
B = Y + Z (B is a known number)

From the 2nd and 3rd equations, you get Y = (A - B).  Then X = 2* (A - B).  Sufficient.
板凳
发表于 2011-1-11 14:17:01 | 只看该作者
200 people.  X only choose A. Y only choose B. Z choose both A and B.  N choose neither.

200 = X + Y + Z + N.
A = X + Z (A is a known number)
B = Y + Z (B is a known number)

The stimulus asks for X

1) Z = N.  Then
200 = X + Y + 2Z.  
A = X + Z (A is a known number)
B = Y + Z (B is a known number)

But this won't help us since if you add the 2nd and 3rd equation, you would get the same equation (A +B has to equal 200, though).  Insufficient.

2) X = 2Y.  Then
200 = 2Y + Y + Z + N = 3Y + Z + N
A = 2Y + Z (A is a known number)
B = Y + Z (B is a known number)

From the 2nd and 3rd equations, you get Y = (A - B).  Then X = 2* (A - B).  Sufficient.
-- by 会员 sdcar2010 (2011/1/11 12:58:52)



可是题目并没有告诉A和B的值呀?
地板
 楼主| 发表于 2011-1-11 14:58:35 | 只看该作者
题中并没有A、B的值啊
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