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请教两个JJ题目

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楼主
发表于 2004-5-11 00:43:00 | 只看该作者

请教两个JJ题目

  4月JJ438题:438 ps. 1/6 the student of the school at least know how to play one instrument,86 student of the school know how to play two or three instruments, there are 800 at school , if you choose 3 students out , what is the possibility that the 3 students exactly play one instrument? (those statistis are not exactly the same as the original question on the screen)


   我的计算是:800*1/6-86=A个


   那么概率是C(3,A)/ C(3,800),和HORSEFISH的答案不一致,horsefish评论: 1/236
思路: 3/(800*1/6-86)     请NN指点一下


  另310题:310 ps。10个人进一饭店,但店里只剩四把椅子,问怎么做法?(本月出现两次)


   我觉得就是从10个人中选4个人,C(4,10),有人做P(4,10),不是很理解,请教

沙发
发表于 2004-5-11 07:32:00 | 只看该作者

同意

第二是C4 10

板凳
 楼主| 发表于 2004-5-11 11:32:00 | 只看该作者
   那第一个题目呢??请教大家
地板
发表于 2004-5-11 12:00:00 | 只看该作者
同意你的解答,希望大家来讨论了
5#
发表于 2004-5-11 19:44:00 | 只看该作者

第一题我觉得你是正确的,还有一种做法是利用乘法原理

A/800*(A-1)/(800-1)*(A-2)/(800-2)

第二题我认为应该是P(4,10),因为出了从10个人中选出4人之外,还要考虑4个人各坐哪把椅子.也可以这样考虑: 四把椅子ABCD, A上可做10人, B上9人, C上8人, D上7人,那么坐法就是10*9*8*7人, 和P(4,10)的结果是一样的.

6#
 楼主| 发表于 2004-5-11 23:44:00 | 只看该作者

  我觉得甲乙丙丁-四个人坐和乙甲丙丁坐是一样的,不能用P(4,10)

  我对这些理解不好,请指教

7#
发表于 2004-5-12 00:29:00 | 只看该作者
这也许要看原题怎么说的了,如果原题认为坐哪把椅子无所谓那么应是C,否则应该是P, 考试的时候看题目怎么说吧.
8#
发表于 2004-5-13 23:54:00 | 只看该作者
以下是引用dreadpower在2004-5-11 0:43:00的发言:

  4月JJ438题:438 ps. 1/6 the student of the school at least know how to play one instrument,86 student of the school know how to play two or three instruments, there are 800 at school , if you choose 3 students out , what is the possibility that the 3 students exactly play one instrument? (those statistis are not exactly the same as the original question on the screen)


   我的计算是:800*1/6-86=A个


   那么概率是C(3,A)/ C(3,800),和HORSEFISH的答案不一致,horsefish评论: 1/236
思路: 3/(800*1/6-86)     请NN指点一下


  另310题:310 ps。10个人进一饭店,但店里只剩四把椅子,问怎么做法?(本月出现两次)


   我觉得就是从10个人中选4个人,C(4,10),有人做P(4,10),不是很理解,请教



谢谢dreadpower.
9#
发表于 2004-5-14 00:21:00 | 只看该作者
以下是引用dreadpower在2004-5-11 0:43:00的发言:

  4月JJ438题:438 ps. 1/6 the student of the school at least know how to play one instrument,86 student of the school know how to play two or three instruments, there are 800 at school , if you choose 3 students out , what is the possibility that the 3 students exactly play one instrument? (those statistis are not exactly the same as the original question on the screen)


   我的计算是:800*1/6-86=A个


   那么概率是C(3,A)/ C(3,800),和HORSEFISH的答案不一致,horsefish评论: 1/236
思路: 3/(800*1/6-86)     请NN指点一下


强烈同意:C(3,A)/ C(3,800)

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