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lsat-17-1-7

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楼主
发表于 2004-4-1 11:52:00 | 只看该作者

lsat-17-1-7

A population of game ducks at a western lake contains 55 males to every 45 females, while a population of game ducks at an eastern lake contains 65 males for every 35 females. Among those ducks that have not yet bred there are only slightly more males than females, but among older ducks the number of males greatly exceeds the number of females. Because there are appreciably more males among adult ducks than among young ducks, we can infer that the greater the disparity in overall sex ratios, the greater the percentage of older male ducks in the population.

Which one of the following can be inferred from the passage?

(A) The population of game duck at the western lake contains a lower percentage of adult males than the population at the eastern lake contains.

(B) The population of game duck at the eastern lake contains a higher percentage of nonadult game ducks than the population at the western lake contains.

(C) The total number of male game ducks is higher in the eastern lake's population than in the western lake population.

(D) The number of nonadult ducks hatched in a breeding season is higher in the eastern lake's population than in the western lake's population.

(E) Adult female game ducks outnumber nonadult female game ducks in the eastern lake's population.

Ans:A!! 为什么C不是答案呢?


沙发
发表于 2004-4-1 14:35:00 | 只看该作者
题干说西湖,M:F=55:45,东湖M:F=65:35,对于小鸭鸭,公比母的多一点点,但是老鸭鸭公比母多好多。因此我们可以推断两性差别的比率越大,那么老公鸭在整个鸭口里占的比率越大。那么东湖两性差别比率大,所以东海的老公鸭占的比率大,这是A所说的。这里比较的是个比率问题,C说的是总数问题,比率大不一定能说明总数大。所以C不能作为答案。
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