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楼主
发表于 2010-1-22 11:12:00 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
Q14:

A three-digit code for certain logs uses the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 according to the following constraints.  The first digit cannot be 0 or 1, the second digit must be 0 or 1, and the second and third digits cannot both be 0 in the same code.  How many different codes are possible?



A.  144

B.  152

C.  160

D.  168

E.  176

Answer: B Why?
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沙发
发表于 2010-1-22 12:51:07 | 只看该作者
first digit has 8 possibilities. 2~9
if second digit is 1, then third digit has 10 possible values. that gives us 8 x 10 = 80
if second digit is 0, then third digit has 9 possible values, and that gives us 8x9 = 72

80 + 72 = 152
板凳
 楼主| 发表于 2010-1-22 16:12:20 | 只看该作者
Thank you.
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