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help-abt GWD math

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楼主
发表于 2009-3-20 10:15:00 | 只看该作者

help-abt GWD math

Q6:


    

A box
contains 10 light bulbs, fewer than half of which are defective.  Two bulbs are to be drawn simultaneously from
the box.  If n of the bulbs in box are
defective, what is the value of n?


    

(1)   The probability that the two bulbs to be drawn will be defective
is 1/15.


    

(2)   The probability that one of the bulbs to be drawn will be defective
and the other will not be defective is 7/15.


    

                  


    

A.
Statement (1) ALONE is sufficient, but statement (2) alone is not
sufficient.


    

B.
Statement (2) ALONE is sufficient, but statement (1) alone is not
sufficient.


    

C. BOTH
statements TOGETHER are sufficient, but NEITHER statement ALONE
is sufficient.


    

D. EACH
statement ALONE is sufficient.


    

E.
Statements (1) and (2) TOGETHER are NOT sufficient.


    

                                                                                                                                                                       
Answer: C

Is it bc for 2), x defective, 10-xnot defective, so the probability should be cx1*c10-x1




    

Q10:


    

Six
cards numbered from 1 to 6 are placed in an empty bowl.  First one card is drawn and then put back
into the bowl; then a second card is drawn. 
If the cards are drawn at random and if the sum of the numbers on the
cards is 8, what is the probability that one of the two cards drawn is numbered
5 ?


    

 


    

A.       
1/6


    

B.       
1/5



    

C.       
1/3


    

D.      
2/5


    

E.       
2/3


    

Answer any clue?


    

The operation Θ is defined by x Θ y = 1/x + 1/y for all nonzero
numbers x and y.  If z
is a number greater than 1, which of the following must be true?


    

 


    

 


    

  I.  x Θ (-z) = 0


    

             II.  z
Θ  = 1


    

            III. 
 Θ  = z


    

 


    

 


    

A.          I only


    

B.          I and II
only


    

C.          I and
III only


    

D.          II and
III only


    

E.          I, II,
and III


    

 
Answer:E

Why 1) is right? we know nothing about the relation btwn x and z


    

Q37:


    

In a
meeting of 3 representatives from each of 6 different companies, each person
shook hands with every person not from his or her own company.  If the representatives did not shake hands
with people from their own company, how many handshakes took place?


    

 


    

A.     
45


    

B.     
135


    

C.     
144


    

D.    
270


    

E.     
288


    

Answer: B any clue
    


[此贴子已经被作者于2009-3-20 10:44:22编辑过]
沙发
发表于 2009-3-21 04:20:00 | 只看该作者

hi,hellokelly,不好意思啊,我这几天在弄语文,没上来看过数学,现在来看看。


    

Q6,你是不是认为选B?


    

我觉得这个问题选D,它说 two bulbs are to be drawn simultaeously,说明了没有拿出来再放回去的可能。


    

条件(1)拿出来的两个球都是defective的概率是1/15,所以是C(10,N)*C(9,n-1)=1/15


    

条件(2):拿出第一个是defective第2个不是:C(10,N)*C(9,10-N)=7/15


    

貌似都能算出来吧

板凳
发表于 2009-3-21 04:23:00 | 只看该作者

question10,这个问题就是涉及到了拿出来还能放回去的问题,那么你想拿出来随便拿两张是36种拿法,能够出来8的有(2,6),(6,2),(3,5),(5,3),(4,4)那么当中含有5的有(3,5)和(5,3)两种啊,所以是2/5,答案选D

地板
发表于 2009-3-21 04:34:00 | 只看该作者

18个人,ABCDEF公司


    

A公司的3个人和其他公司的人握手,一个人握15次,3个人就是45


    

B公司,已经和A握过了,同理,36次,其中每个人握12次


    

C公司27次


    

D公司18


    

E公司9次


    

全部相加就等于135次啦。希望能够帮到你。


    



    

还有一种思路,你就先算它们随便握,然后减去和自己公司握手的也行,就是C(18,2)-C(3,2)*6=135


    



    

第10题我看不懂啊

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