一道不明白的破解prep逻辑 请路过解惑

破解逻辑prep48.   (34221-!-item-!-188;#058&007550)

Parasitic wasps lay their eggs directly into the eggs of various host insects in exactly the right numbers for any suitable size of host egg.  If they laid too many eggs in a host egg, the developing wasp larvae would compete with each other to the death for nutrients and space.  If too few eggs were laid, portions of the host egg would decay, killing the wasp larvae.

Which of the following conclusions can properly be drawn from the information above?

(A) The size of the smallest host egg that a wasp could theoretically parasitize can be determined from the wasp's egg-laying behavior.

(B) Host insects lack any effective defenses against the form of predation practiced by parasitic wasps.

(C) Parasitic wasps learn from experience how many eggs to lay into the eggs of different host species.

(D) Failure to lay enough eggs would lead to the death of the developing wasp larvae more quickly than would laying too many eggs.

(E) Parasitic wasps use visual clues to calculate the size of a host egg.

我选了C,答案是A

看了答案后我的理解是这样的: 原文中的胡蜂并非一举host egg大小来决定生产多少蛋,而是依据自己的生产多少蛋的能力去寻找合适的host egg来寄生.

所以A里说由 behavior 决定 寄生蛋的大小...

不知道分析的对不对,感觉有些牵强,请路过者解惑^-^

文章中并没有提到Parasitic wasps learn from experience,也许P知道放多少个egg是天生的,所以C不对.

其实答案A是文章第一句的改写.