ChaseDream
搜索
返回列表 发新帖
查看: 1310|回复: 1
打印 上一主题 下一主题

feifei120

[复制链接]
楼主
发表于 2009-10-3 16:31:00 | 只看该作者

feifei120

120. In Europe, schoolchildren devote time during each school day to calisthenics. North American schools rarely offer a daily calisthenics program. Tests prove that North America children are weaker, slower, and shorter-winded than European children. We must conclude that North American children can be made physically fit only if they participate in school calisthenics on a daily basis.

 

Which one of the following is assumed in the passage?

 

A.       All children can be made physically fit by daily calisthenics.

B.        All children can be made equally physically fit by daily calisthenics.

C.        Superior physical fitness produces superior health.

D.       School calisthenics are an in indispensable factor in European children’s

E.        North American children can learn to eat a more nutritious diet as well as to exercise daily.

答案为D

我选的A。我的思路:欧洲,孩子们有C;美国,孩子们无C。美国,孩子们身体不如欧洲孩子好。结论,美国孩子要想身体变好只能参加C。

A选项:所有孩子通过C身体都能变好。表述了同质性。(因为C不一定适合美国孩子)

为什么选D啊?

大家帮帮我。

沙发
发表于 2009-10-4 02:14:00 | 只看该作者
提醒:题目中的结论是only if

也就是说题目中最后下的结论是只有通过c孩子们才能变好,暗含着意思是用别的什么手段美国孩子也好不了,那么意味着c是唯一能使孩子好的原因,所以D说c是欧洲孩子好的不可或缺的因素(唯一性)

至于A选项,没有体现唯一性,就算有了A的假设,所有孩子都能通过c变好,也不能够证明我美国孩子只有通过c才能变好,也不能否定有其他方法,所以A不是答案
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2024-9-27 07:18
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2023 ChaseDream.com. All Rights Reserved.

返回顶部