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prep2里的一道题,请教!

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楼主
发表于 2008-7-9 23:09:00 | 只看该作者

prep2里的一道题,请教!

恶~~~~~这道题没读明白啊,别说做了,呵呵,不知道大家做模考遇没遇上这题

Amy's grade was the 90th pencentile of the 80 grades for her class. Of the 100 grades from another class,19 were higher than Amy's, and the rest were lower . If no other grade was the same as Amy's grade, the amy's grade was what percentile of the grades of the two classes combined.

A 72nd

B 80th

C 81st

D 85th

E 92nd

同学们,帮忙解一下哈!

沙发
发表于 2008-7-10 10:58:00 | 只看该作者
可以这样想, her ranking in her class is 90x80%=72, 8 persons are aheard of her; In another class, 19 persons are ahead of her, combined with two classs, there are total 80+100=180 persons, but 8+19 = 27 persons are ahead of her, so, she is ranking at (180-27)/180= 85% in two classes.


板凳
 楼主| 发表于 2008-7-10 22:52:00 | 只看该作者
谢谢,可我不太明白Amy's grade was the 90th pencentile of the 80 grades for her class. 是什么意思?
地板
发表于 2008-7-10 23:51:00 | 只看该作者
应该是说有90%人的成绩在amy之下吧,跟gmat的算分方法一样啊:-)
5#
 楼主| 发表于 2008-7-11 16:11:00 | 只看该作者
谢谢!
6#
发表于 2008-7-11 20:30:00 | 只看该作者
哦,原来80 grades 是80个人啊
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