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求教,两道Prep数学解法

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楼主
发表于 2007-11-24 06:12:00 | 只看该作者

求教,两道Prep数学解法

The arithmetic mean and standard deviation of a certain normal distribution are 13.5 and 1.5, respectively.  What value is exactly 2 standard deviations less than the mean?

 

(A) 10.5

(B)  11.0

(C)  11.5

(D) 12.0

(E) 12.5

If two of the four expressions x + y, x + 5y, x - y, and 5x - y are chosen at random, what is the probability that their product will be of the form of x^2 - (by)^2, where b is an integer? my wrong answer is 1/2, please advise。。。C(1,3)/C(2,4)

沙发
发表于 2007-11-24 10:36:00 | 只看该作者
 

The arithmetic mean and standard deviation of a certain normal distribution are 13.5 and 1.5, respectively.  What value is exactly 2 standard deviations less than the mean?

 

(A) 10.5

(B)  11.0

(C)  11.5

(D) 12.0

(E) 12.5

这题什么意思啊?同问

板凳
 楼主| 发表于 2007-11-24 13:41:00 | 只看该作者
up
地板
发表于 2007-11-24 15:01:00 | 只看该作者

同问!今天做PREP一上来就是这个题,懵了~~~~

5#
发表于 2007-11-24 15:39:00 | 只看该作者
中位数是13.5,一个标准差为1.5,那么比中位数小两个标准差的值是?答案应该是A吧13.5-1.5*2
6#
发表于 2007-11-24 15:47:00 | 只看该作者

If two of the four expressions x + y, x + 5y, x - y, and 5x - y are chosen at random, what is the probability that their product will be of the form of x^2 - (by)^2, where b is an integer? my wrong answer is 1/2, please advise。。。C(1,3)/C(2,4)

x^2-(by)^2=(x-by)*(x+by), so the only suitable answer is x+y and x-y ,since the total option for the given expressions is C(2,4),the correct answer is 1/c(2,4)=1/6

7#
发表于 2007-11-24 16:03:00 | 只看该作者
同意zaku2000。
8#
发表于 2007-11-24 17:00:00 | 只看该作者
同上。
9#
 楼主| 发表于 2007-11-24 22:33:00 | 只看该作者

谢谢各位,我也是Prep的第一题,请问哪位高职解题思路

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