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向好心人求助一题 GWD29-Q13

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楼主
发表于 2006-8-5 00:18:00 | 只看该作者

向好心人求助一题 GWD29-Q13

GWD29-Q13:

For any positive integer x, the 2-height of x is defined to be the greatest nonnegative integer n such that 2n is a factor of x.  If k and m are positive integers, is the 2-height of k greater than the 2-height of m ?

(1)     k > m

(2)    K除以mis an even integer.    答案是 B, 没看懂题意.

                 


沙发
发表于 2006-8-5 17:16:00 | 只看该作者

if k=8 and m=4, then the 2-height of k is 3, and the 2-height of m is 2.

if k=6 and m=4, then the 2-height of k is 2, the same as the m's

hence, (1) is insufficient.

if k/m is an even integer, supposing that k=m*2t,

then suppose that the 2-height of m is n, that means 2^n is the factor of m and m can be represented as 2^n*s.

we have assumed that k=m*2t, so k=2^n*s*2*t=2^(n+1)*s*t

thus, the 2-height of k is (n+1)

板凳
 楼主| 发表于 2006-8-5 23:22:00 | 只看该作者
Thank you very much for help, but i think you are right, but i still don't understand the question.
地板
 楼主| 发表于 2006-8-5 23:27:00 | 只看该作者
Now, i understand. thank you
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