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clift · 发表于 2011-10-3 10:20:38

如题

jeffxu · 发表于 2011-10-3 10:31:50

Q33 rate=1 mile/100 days = 5280 feet / 2400 hours = 11/5 feet/hr

Q35
J=15+0.2x
K=20+0.1x

(1) 20+0.1x < 25 => x < 50 J=15+0.2x < 15+0.2 * 50=25
(2) x<50

So both are efficient. D.

zy352414882 · 发表于 2011-10-3 10:34:57

B 5280/(100X24)=11/5

D 20+0.1X<25 both can figure out the X limitation. in 1, 15+0.2X<25 so x...... plug it in the 20+0.1X<25
2. plug x<50 in 20+0.1X<25..

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