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集合问题,请教求集合公式

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楼主
发表于 2011-3-8 02:19:28 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
In a group of 68 students, each student is registered for at least one of three classes – History, Math and English. Twenty-five students are registered for History, twenty-five students are registered for Math, and thirty-four students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
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沙发
发表于 2011-3-8 02:56:17 | 只看该作者
25 +25 +34 -(registered for 2) - 2*(registered for 3) = 68

registered for two = 84-2*3-68 =10

Reason: when asked for the classes they registered, those who registered one class answered once, those who registered two classes answered twice, and those who registered three classes answered thrice. Hence the equation above is constructed to remove overcounting.
板凳
 楼主| 发表于 2011-3-8 03:32:01 | 只看该作者
没明白为什么是-2A交B交C呢

记得看到公式是说A+B+C-AB-BC-AC+ABC
地板
发表于 2011-3-8 04:26:38 | 只看该作者
Because your (AB + BC + AC) is not my (registered for exactly two classes) since the former contains my (registered for all three classes) while the latter does not.
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