ChaseDream
搜索
返回列表 发新帖
查看: 1320|回复: 4
打印 上一主题 下一主题

PREP数学题求教,O(∩_∩)O谢谢

[复制链接]
跳转到指定楼层
楼主
发表于 2010-9-24 19:31:05 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
模考时最后一题,感觉题目有点不明确。题目如下:
a hiker walking ar a constant rate of 4 mile per hour is passed by cyclist traveling in the same direction along the same path at a constant rate of 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up?
答案是20. 有点不理解,那个cyclist在passing那个hiker后就等她,题目的意思貌似再pass后还有一个缓冲,这个缓冲的距离应该就是hiker要赶的距离。计算cyclist离hiker多远也要知道时间。但是pass有蕴含时间(⊙_⊙)?而且那个cyclist还停下来等了5分钟。
没理清思路,希望哪位XDJM帮忙看看给下提醒。

还有一题PREP的,答案我也没弄清楚,感觉应该是100%而不是40%。
题目是:the rate of certain chemical reaction is directly proportional to the spuare of the concentration of chemical A present and inversly proportional to the concentration of chemical B present.If the concentration B is incresed by 100% percent while of the following is closest  to keep the reaction rate unchanged? 答案有A increse 100% ,A increse 40% .还有这两个比例decrese的,当然通过题意可以排除decrese如果要保持不变的话。但为什么是40%?0.4^2=0.16啊,100%^2=100%.
O(∩_∩)O谢谢各位啦!
收藏收藏 收藏收藏
沙发
发表于 2010-9-24 19:43:02 | 只看该作者
模考时最后一题,感觉题目有点不明确。题目如下:
a hiker walking ar a constant rate of 4 mile per hour is passed by cyclist traveling in the same direction along the same path at a constant rate of 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up?
答案是20. 有点不理解,那个cyclist在passing那个hiker后就等她,题目的意思貌似再pass后还有一个缓冲,这个缓冲的距离应该就是hiker要赶的距离。计算cyclist离hiker多远也要知道时间。但是pass有蕴含时间(⊙_⊙)?而且那个cyclist还停下来等了5分钟。
没理清思路,希望哪位XDJM帮忙看看给下提醒。

还有一题PREP的,答案我也没弄清楚,感觉应该是100%而不是40%。
题目是:the rate of certain chemical reaction is directly proportional to the spuare of the concentration of chemical A present and inversly proportional to the concentration of chemical B present.If the concentration B is incresed by 100% percent while of the following is closest  to keep the reaction rate unchanged? 答案有A increse 100% ,A increse 40% .还有这两个比例decrese的,当然通过题意可以排除decrese如果要保持不变的话。但为什么是40%?0.4^2=0.16啊,100%^2=100%.
O(∩_∩)O谢谢各位啦!
-- by 会员 daisy727suming (2010/9/24 19:31:05)


我帮你查了下第一题,你看看一个外国网站的解释~
probably the most efficient way to solve this one is with the concept of relative rates.

start at the time when the cyclist passes the hiker.
since they're both traveling in the same direction, their relative rate - i.e., the rate at which the distance between them is changing - is found by subtraction. so, as long as they're both moving the cyclist is gaining on the hiker at a rate of 20 - 4 = 16 mph.
after the cyclist stops, the hiker is making up that distance at a rate of 4 mph. that's only 1/4 as fast as the relative rate during the first 5 minutes, so it will take the hiker 4 times as long to catch back up. so, 4 x 5 = 20 minutes.

if you wanted to, you could calculate the actual distance between the cyclist and the hiker when the cyclist stops: (16 mi/h)(1/12 h) = d, where "1/12 h" is five minutes. then you could find the time taken by the hiker alone to travel the same distance "d".
you don't have to do this, though, if you realize the 1:4 ratio referenced above

第二题还在看!
板凳
发表于 2010-9-24 19:52:10 | 只看该作者
the rate of certain chemical reaction is directly proportional to the spuare of the concentration of chemical A present and inversly proportional to the concentration of chemical B present.If the concentration B is incresed by 100% percent while of the following is closest  to keep the reaction rate unchanged?

我的思路是这样的
从这个题目中我们可以得到这样一个抽象的式子 r = kA^2 / B

我们把后来的情况分别看成A as A', and the new concentration of B as B'. 题目说新的rate=老的rate
我们式子可以写成k (A')^2 / B' = k A^2 / B

B is increased by 100%, 因此B' = 2B.
所以可以写成k (A')^2 / 2B = k A^2 / B

通过约分化简:
(A')^2 = 2 A^2

A' = 2A的平方 .
2开方为1.4
3开方为1.7
因此A‘为1.4A,则增加了0.4
希望能看明白哦!
地板
 楼主| 发表于 2010-9-24 20:49:35 | 只看该作者
呵呵,O(∩_∩)O谢谢!好迅速啊,刚才在看语法,再上来瞧瞧已经都解决了。太谢谢啦!
5#
发表于 2010-9-24 21:12:41 | 只看该作者
呵呵,O(∩_∩)O谢谢!好迅速啊,刚才在看语法,再上来瞧瞧已经都解决了。太谢谢啦!
-- by 会员 daisy727suming (2010/9/24 20:49:35)



不用不用!懂了就好!
加油复习哦!!!
您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2025-11-5 19:42
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2025 ChaseDream.com. All Rights Reserved.

返回顶部