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【求助】一道kaplan的数学题

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楼主
发表于 2020-10-10 15:49:34 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
Three is the largest number that can divide evenly into both 27 and the positive integer x, while 10 is the largest number that can divide evenly into both 100 and x. Which of the following is the largest possible number that could be divided into x and 2,100?
A 30
B70
C 210
D 300
E 700
正确答案是c,求NN解释下这道题的题目意思和解题过程
下面是Kaplan对这道题的解释,但我没看懂
Analyze the Question:
We are told that 3 is the greatest common factor of 27 and x, and that 10 is the greatest common factor of 100 and x. Since 3 and 10 have no factors in common, x must be some multiple of 3 × 10 = 30.
Identify the Task:
We must find the largest number that will divide evenly into x and 2,100.
Approach Strategically:
Begin by considering the possible values of x. If x were an even multiple of 30, such as 60, x and 100 would share a common factor of 20. Since the problem says that 10 is the greatest common factor of x and 100, x must be an odd multiple of 30. That allows us to eliminate choices (B), (D), and (E). Since we are looking for the largest possible number that divides evenly into x and 2,100, let’s check (C): The greatest common factor of 27 and 210 is 3 because 27 = 3 × 3 × 3 and 210 = 2 × 3 × 5 × 7 (both have at most a single 3 in common). By the same token, the greatest common factor of 100 and 210 is 10 because 100 = 2 × 2 × 5 × 5 and 210 = 2 × 3 × 5 × 7 (both have at most the 2 × 5 in common).
The correct answer is Choice (C).
Confirm Your Answer:
All the answer choices divide evenly into 2,100. Even if we counted all the multiples of 30, we could eliminate choices (B) and (E) because 7 does not divide into all multiples of 30. The greatest common factor of 100 and 300 is 100, which is too large, eliminating choice (D). The greater of the 2 remaining choices is 210, divisible by both 3 and 10. We can be confident that the correct answer is Choice (C).


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沙发
 楼主| 发表于 2020-10-10 16:49:44 | 只看该作者
自己顶一下
板凳
发表于 2020-10-11 06:59:04 | 只看该作者

被27和X同时整除的最大为3,那么X=3*a. a=1, 2, 5, 7,11,13等质数(将27分解为3*3*3)
被100和x同时整除的最大为10,那么x=2*5*b,b=1, 7, 11, 13等质数(将100分解为2*5*2*5)
综上,被2100和x同时整除的最大为: =2*5*3*7 (将2100分解为3*7*2*5*2*5)
地板
 楼主| 发表于 2020-10-13 19:35:51 | 只看该作者
长丝弓 发表于 2020-10-11 06:59
被27和X同时整除的最大为3,那么X=3*a. a=1, 2, 5, 7,11,13等质数(将27分解为3*3*3)
被100和x同时整除的 ...

请问b可以等于的质数里面没有3呢
另外,对于题目里面three is the largest number that can divide evenly... 不是被动语态可以翻译成被整除么

求求nn再回复下,感恩~
5#
 楼主| 发表于 2020-10-13 19:36:44 | 只看该作者
长丝弓 发表于 2020-10-11 06:59
被27和X同时整除的最大为3,那么X=3*a. a=1, 2, 5, 7,11,13等质数(将27分解为3*3*3)
被100和x同时整除的 ...

请问b可以等于的质数里面没有3呢
另外,对于题目里面three is the largest number that can divide evenly... 不是被动语态可以翻译成被整除么

求求nn再回复下,感恩~
6#
发表于 2020-10-13 21:00:28 | 只看该作者
还没想好名字 发表于 2020-10-13 19:36
请问b可以等于的质数里面没有3呢
另外,对于题目里面three is the largest number that can divide evenl ...

b可以等于的质数里有1个3, 我上个回复的帖子里,写的第一个字就是“被”啊。。。
7#
 楼主| 发表于 2020-10-15 10:03:23 | 只看该作者
长丝弓 发表于 2020-10-13 21:00
b可以等于的质数里有1个3, 我上个回复的帖子里,写的第一个字就是“被”啊。。。 ...

我是想问divide into 没有被动语态 为啥可以翻译成被动呀
8#
发表于 2020-10-16 10:34:17 | 只看该作者
还没想好名字 发表于 2020-10-15 10:03
我是想问divide into 没有被动语态 为啥可以翻译成被动呀

谢谢提醒,准确的表达应该为:
27和x同时被3整除,....
100和x同时被10整除,
2100和X同时被以下数(最大)整除:210
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