zk: in order for w*x*y*z*k to be less than 0, an odd number of varibles among w, x, y, z, k must be less than 0, so if this number equals to 1, then k > z > y > x > 0, implies zk > 0; if the number is 3, then k > z > 0, implies zk > 0; if the number is 5, then z < k < 0, implies zk > 0; thus zk must be greater than 0 if w < x < y < z < k and w*x*y*z*k < 0; xy: the same thing applies: if the number is 1, then k > z > y > x > 0, implies xy > 0; if the number is 3, then k > z > 0 and x < y < 0, implies xy > 0; if the number is 5, then x < y < z < k < 0, implies xy > 0; so im guessing only one of these two is in the answer choices; |