请教t-4-q20

sweetkelly

T-4-Q20 天山-7-22

The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

文章涉及两个城市M，P本身4年前和现在犯罪率的比较，结论是现在M比P犯罪受害者多。

横向比较背景一致

The argument above is flawed because it fails to take into account

 

1. Changes in the population density of both Meadowbrook and Parkdale over the past four years.

2. How the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

3. The ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

4. The violent crime rates in Meadowbrook and Parkdale four years ago

5. How Meadowbrooks’ expenditures for crime prevention over the past four years compare to Parkdale’s expenditures.

我怎么觉得应该选B呢？应该和人口的增长率来确定现在犯罪的百分比吧，请指教

sweetkelly

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sweetkelly

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