ChaseDream
搜索
返回列表 发新帖
查看: 782|回复: 0
打印 上一主题 下一主题

急求本月jj中一类题目的思路,很快考了,谢谢大家

[复制链接]
楼主
发表于 2006-12-15 18:11:00 | 显示全部楼层
以下是引用zhangxiaofff在2006-12-15 17:40:00的发言:

108. 一个数除以10的余数是多少?1) 除以52  2) 除以21,答案:C
答案:C(余7

这类题目是啥思路来,我每次一看就晕了,急求大虾相助,非常感谢

(1) a number divided by 5 has reminder = 2, means the number must have unit digit = 2 or 7 (e.g. 7, 12, 17, 22....)

It is not sufficient to answer the question, as 12/10, reminder = 2.  17/10, reminder = 7.

(2) the number divided by 2 will have reminder = 1.  This means the number is odd number.

(2) alone cannot answer the question.

But combining (1) and (2)...,

So we can tell the number must have unit digit = 7.  When 17 is divided by 10, the reminder must be 7.

So answer is (c).

您需要登录后才可以回帖 登录 | 立即注册

Mark一下! 看一下! 顶楼主! 感谢分享! 快速回复:

手机版|ChaseDream|GMT+8, 2025-7-24 20:48
京公网安备11010202008513号 京ICP证101109号 京ICP备12012021号

ChaseDream 论坛

© 2003-2025 ChaseDream.com. All Rights Reserved.

返回顶部