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OG11 Math Review 不懂的地方,求助!

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楼主
发表于 2007-7-1 13:32:00 | 只看该作者

OG11 Math Review 不懂的地方,求助!

N1

P119

For a final example, consider an experiment with events A,B, and C for which P(A)=0.23, P(B)=0.40, and P(C)=0.85.  Also, suppose that events A and B are mutually exclusive and events B and C are independent.  Then we can get P(A or B)= 0.63 and P(B or C)= 0.91.  Note that P(A or C) and P(A and C) cannot be determined using the information given.  But it can be determined that A and C are not mutually exclusive since P(A)+P(C)=1.08, which is greater than 1, and therefore cannot equal P(A or C); from this it follows that P(A and C)≥0.08.  One can also deduce that P(A and C)≤P(A)=0.23, since A∩C is a subset of A, and that P(A and C)≤P(C)=0.85 since C is a subset of AC .  Thus, one can conclude that 0.85≤P(A or C)≤1 and 0.85≤P(A or C)≤0.23.

自从划线的地方开始看不懂了。

Q1 “since C is a subset of AC” 这句话能推出P(A and C)≤P(C)=0.85吗?是不是改写为AC is a subset of C.

Q2 最后一句话到底是怎么推出来的啊?我的脑袋转不过来!总觉得0.85≤P(A or C)≤0.23.

应该是0.85≤P(A C)≤0.23

谢谢!

沙发
发表于 2007-7-1 21:16:00 | 只看该作者

因为题目已说了cannot equal P(A or C),所以最后那句说的A并C的情况是A属于C

[attachimg]59281[/attachimg]


[此贴子已经被作者于2007-7-1 21:17:35编辑过]

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板凳
 楼主| 发表于 2007-7-2 23:17:00 | 只看该作者
谢谢!
地板
发表于 2008-9-16 11:01:00 | 只看该作者

0.85≤P(A or C)≤0.23

请问为什么0.85≤0.23?
                

是否应该改成0.23≤P(A or C)≤0.85?

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