SDCAR2010【游戏入门】64-2 解析

sdcar2010

64-2
党中央需要派党代表去三个公司：Verizon, Yahoo，和 Zillow。五个党代表候选人是：James, Keven, Liang, Nemo, 和 Ostrich。每个公司有一个党代表。没有任何党代表被派到一个以上的公司。派遣细则是：
Either Keven or Nemo, but not both, 被任命为党代表。
如果 James 去当党代表，那么 Keven 也得当。
如果 Ostrich 去 Verizon 当党代表，那么 Keven 不能去 Yahoo 当党代表。
如果 Liang 去当党代表，那家公司是 Zillow 。

Analysis:
The original English version of this problem is a good test for your reading comprehension. As usual, the key to solve the question is to clearly understand the rules.

First, this is a hybrid game of grouping: in-and-out type coupled with matching type. We have one and ONLY one open seat for each of the three companies: V, Y, and Z. The five candidates are J, K, L, N, and O. One of K or N HAS to be chosen. J-->K. If O matches with V, then K does not match with Y. L HAS to be in Z, if chosen. The final diagram can be found in the following picture:

SDCAR2010 【游戏入门】64-1 解析
SDCAR2010【游戏入门】64-3 解析

sdcar2010

Impressive. You just need more time to train your brain and increase your speed.

quite time consuming, I guess I am not familiar with these kinds of questions at all.

-- by 会员 HarrisZheng (2011/12/12 18:36:30)

sdcar2010

Another way to solve this question:

If O in V, then K is NOT in Y.
If K is IN, then K must be in Z. So L is out, together with N. That gives us K & O in. Unfortunately, that is not one of the choices. So K is out, and N is in.

If N is in and N is in Z, than both K and L are out. That gives us N &O in. Unfortunately that is not one of choices.

If N is in and N is in Y, then both L and O can be in Z. That makes Z the correct answer.

9

if J+ then K+ and N- so AB out
K and N can not be both +  so D out
If K&L both + then O=V L=Z K=Y  so C out
thus E

-- by 会员 HarrisZheng (2011/12/12 17:34:47)

HarrisZheng

quite time consuming, I guess I am not familiar with these kinds of questions at all.

HarrisZheng

12
which condition will allow K- lead to J-
A out
B if K- then N+ , does not lead to J- ,out
C if K- then N+ O+ , does not lead to J-, out
D if K- then N+ J-, bingo
E if K- then N+ O- J+, out

Notice that: James and Nemo are not both assigned ≠ Either  James or Nemo is assigned, but not both .
It can be this: both J and N are not assigned.

HarrisZheng

11
A If J=Z then K+ L- N- , can be true for now
B If K=Z then N- L-, can be true  for now
C If N=Z the K-, J-,L- can not have 3- ,
so C

HarrisZheng

10
If K=Y then O≠V and N-
If L+ then K=Y L=Z O≠V  J=V ,
If L- then K=Y O=Z J=V
so in each case, J always =V
thus A

HarrisZheng

9

if J+ then K+ and N- so AB out
K and N can not be both +  so D out
If K&L both + then O=V L=Z K=Y  so C out
thus E

HarrisZheng

8
if K- then J-
so choices CD out
if J+ then K+ and N- so E out
K and N can not be both + so B out
thus A

HarrisZheng

7  use + to stand for assigned , - for not assigned
A J+ K- out
C L=V our
D K+ N+ out
E O=V and K=Y out
thus B