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今天在一个帖子的讨论中,是非限定型定语从句which指代的问题,我对比研究了大全SEC01-18这道题, Schoolintegrationplans that involve busing between suburban and central-city areashave contributed,according to a recent study, to significant increases inhousing integration, which, in turn,reduces any future need for busing. (A) significantincreases in housing integration,which, in turn, reduces (B) significantintegration increases in housing,which, in turn, reduces (C) increasehousing integration significantly,which, in turn, reduces (D) increasehousing integration significantly, inturn reducing (E) significantlyincrease housing integration,which, in turn, reduce 正确答案为A,这道题中 OG的解释是 which明显指代 housing integration。 In choice E, whichclearly refers to housing integration, making the plural verb reduce incorrect.This question is of middle difficulty. 我也没想明白为什么从逻辑上可以指代A。 所以,我想在GMAT考试中,是否GMAT认为所有的非限定型定语从句都是直接指代离他最近的名词。 为了验证这个假设,我选取了OG12作为样本,用里面的140道题进行验证。 验证结果如下: 题号 表现 是否符合规则 OG12-1 who yes OG12-43 "题干出现where,但是没有指代前面 的名词,表现是错误。正确答案是many of whom指代前面的population yes OG12-49 system,which yes OG12-63 出现在错误选项中,which没有就近指代day yes OG12-66 which指代前面的the killer whale yes OG12-71 从逻辑上看which应该指代的是游客, 但是跳跃指代了所以该选项错误。 yes OG12-86 which指代前面的profits yes OG12-107 which指代前面X射线 yes OG12-110 who指代前面的一只飞利浦 yes
总共有9道题,里面涉及了非限定型定语从句,这里面如果非限定性定语从句的关系代词没有指代离他最近的名词,OG都冠以指代不清。 那么就现在看来,GMAT认为非限定型定语从句的关系代词必须指代离他最近的名词。 如果真的成立,那么这个规则可以作为判断一个选项正确与否的必要非充分条件。
而如果是限定型定语从句,则其关系代词可以跳跃指代。 例如 OG12-126 126. The use of lie detectors is based on the assumption that lying produces emotional reactions in anindividual that, in turn, create unconscious physiological responses.
A:that, in turn, createunconscious physiological responses B:that creates unconsciousphysiological responses in turn C:creating, in turn, unconsciousphysiological responses D:to create, in turn,physiological responses that are unconscious E:who creates unconsciousphysiological responses in turn 答案为A 则可以跳跃指代,请大家指正。 |
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