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What is the greatest number for n such that 2^n divides 8!/2! ? 我的最后一道题 很明确
8!/2! = 2^3*2*2^2*2/2 = 2^6
n = 6
On a side note, if you pay attention to my GMAT challenging question of this one:
"GMAT 数学题(7)
n 为正整数。问 n 最大为多少能让 (2^6)! 整除 2^n ?"
you would have a very easy time to solve the real GMAT question!
Because the question basically hinges on the question "n 为正整数。问 n 最大为多少能让 (2^3)! 整除 2^n ?"
We know the answer to the above question is 2^3 -1 = 7. Then since the question is asking "n 为正整数。问 n 最大为多少能让 (2^3)! /2! 整除 2^n ?", we simply minus 1 from 7 and you got 6! |
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