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新书学酷字22th~~~

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楼主
发表于 2010-12-26 23:13:42 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
圆盘钥匙题~
小狼童鞋说了 圆形要除以N~~~~但是为什么捏?……
还有 有童鞋说——圆形排序是公式2/(n-1) 直接代入就行~~~~代入后跟小狼的答案是一样哒 但是又是为什么捏……
求助于走过路过的战友们~thx^^

------啊 我在CD发的处女主题~~~
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沙发
发表于 2010-12-26 23:21:42 | 只看该作者
If n different people are sitting around a table, the possibility of 2 persons sitting next to each other is 2/(n-1).

1) Total possible arrangements of n people on a table = n! / n = (n-1)!
2) Total possible arrangements of n-1 people (assuming those two sitting together would be treated as a single person) = 2* (n-1)! / (n-1) = 2* (n-2)!  There is a 2 in the equation because the two persons are not identical.

The possibility of 2 persons sitting next to each other = 2* (n-2)! / (n-1)! = 2/(n-1)
板凳
发表于 2010-12-26 23:25:37 | 只看该作者
Total possible arrangements of n people on a table = n! / n = (n-1)!

The reason to devide n! by n is that when your connect the head to tail of a linear arrangement to form a circular arrangement, you will find that for each circular arrangement, you have n different possible linear arrangements because you can cut the ring formed at n different places to get a different linear arrangement!
地板
 楼主| 发表于 2010-12-26 23:32:46 | 只看该作者
If n different people are sitting around a table, the possibility of 2 persons sitting next to each other is 2/(n-1).

1) Total possible arrangements of n people on a table = n! / n = (n-1)!
2) Total possible arrangements of n-1 people (assuming those two sitting together would be treated as a single person) = 2* (n-1)! / (n-1) = 2* (n-2)!  There is a 2 in the equation because the two persons are not identical.

The possibility of 2 persons sitting next to each other = 2* (n-2)! / (n-1)! = 2/(n-1)
-- by 会员 sdcar2010 (2010/12/26 23:21:42)



灰常灰常感谢~~
但是我依然不能理解的是:
第一步 1)中为什么分母要除以n.......
貌似这是个基本知识。。。但一时半会儿实在是记不起为啥来了。。囧
5#
发表于 2010-12-26 23:34:32 | 只看该作者
Linear: ABC, BCA, CAB
circular: Only -ABC-
6#
 楼主| 发表于 2010-12-26 23:48:29 | 只看该作者
Linear: ABC, BCA, CAB
circular: Only -ABC-
-- by 会员 sdcar2010 (2010/12/26 23:34:32)


额果断纠结了。。。
LINEAR的话 不是应该有 ABC,ACB,BAC,BCA,CAB,CBA 一共A33=六种咩
7#
发表于 2010-12-26 23:51:31 | 只看该作者
Linear: ACB, CBA, BAC
circular: Only -ACB-

This and the above examples demonstrate that for one circular arrangement of n things, you have n linear arrangement of n things.

The reason to devide n! by n is that when your connect the head to tail of a linear arrangement to form a circular arrangement, you will find that for each circular arrangement, you have n different possible linear arrangements because you can cut the ring formed at n different places to get a different linear arrangement!
8#
发表于 2010-12-26 23:52:06 | 只看该作者
凡是遇到了钥匙链的,我们都默认一个规律:少算一个元素。就对了!
9#
 楼主| 发表于 2010-12-27 00:21:18 | 只看该作者
Linear: ACB, CBA, BAC
circular: Only -ACB-

This and the above examples demonstrate that for one circular arrangement of n things, you have n linear arrangement of n things.

The reason to devide n! by n is that when your connect the head to tail of a linear arrangement to form a circular arrangement, you will find that for each circular arrangement, you have n different possible linear arrangements because you can cut the ring formed at n different places to get a different linear arrangement!
-- by 会员 sdcar2010 (2010/12/26 23:51:31)


哈!我明白啦~~~~就是
圆变直线要乘以N
直线变圆要乘以1/N
啦~~~谢谢你! 真是给我解释的好费力气~~~不过这下终于砂锅到底嘞~~嘿嘿
GOOOOOOD LUUUUUUCK FOR U!!!!!!!SINCERELY~
10#
 楼主| 发表于 2010-12-27 01:19:15 | 只看该作者
凡是遇到了钥匙链的,我们都默认一个规律:少算一个元素。就对了!
-- by 会员 rinelylove (2010/12/26 23:52:06)


嗯呢 升级版的 好记!
美女是快考试了么? 加油+好运气!!!
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